Math Problem Statement
Solution
Let's break down and solve the problem step by step.
We are given the complex number , where . The goal is to compute the sum of various arguments:
Step 1: Calculate
We know that . In polar form, the argument of corresponds to the angle made with the positive real axis. Since lies on the negative imaginary axis, the argument is:
Step 2: Calculate
The conjugate of , denoted by , is . The argument of , which lies on the positive imaginary axis, is:
Step 3: Calculate
The modulus of is:
Since is a real positive number, the argument of any positive real number is 0:
Step 4: Calculate
We previously found . Now we need to compute the argument of this real number. Since is a negative real number, the argument of any negative real number is :
Step 5: Calculate
The imaginary part of is , which is a negative real number. Again, the argument of any negative real number is :
Step 6: Sum all the arguments
Now, we sum all the computed arguments:
Step 7: Express in the form
We have , which can be written as:
Here, and . Since and are coprime, the sum is:
Thus, the value of is 3.
Would you like further details or have any additional questions? Here are some related questions to expand your understanding:
- What is the geometrical interpretation of the argument of a complex number?
- How do you compute the modulus of a complex number in general?
- What is the argument of the conjugate of a complex number, and why?
- How does the argument behave for purely real numbers, both positive and negative?
- Can the argument of a complex number ever exceed or be less than ?
Tip: When dealing with complex numbers, always remember that arguments are taken in the principal range .
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Math Problem Analysis
Mathematical Concepts
Complex Numbers
Arguments of Complex Numbers
Conjugate of Complex Numbers
Modulus of Complex Numbers
Formulas
arg(z) = θ
arg(¯z) = -θ
arg(|z|) = 0 if |z| > 0
arg(negative real number) = π
Theorems
Argument of a complex number
Properties of conjugate and modulus of complex numbers
Suitable Grade Level
Grades 11-12
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