https://file.aiquickdraw.com/mathbot/file/1723939762026j38hyvl2.jpg

Let's break down and solve each problem from the assignment in the image you provided:

### 1. **Calculate the volume in mL of 0.5M NaCl stock solution to make 100 mL of a diluted solution with a concentration of 0.03M.**

This is a dilution problem, and we can use the formula:

\[
C_1 V_1 = C_2 V_2
\]

Where:
- \(C_1\) = initial concentration (0.5 M)
- \(V_1\) = volume of the stock solution needed (in mL)
- \(C_2\) = final concentration (0.03 M)
- \(V_2\) = final volume (100 mL)

Substituting the values:

\[
(0.5 \, \text{M}) \times V_1 = (0.03 \, \text{M}) \times (100 \, \text{mL})
\]

\[
V_1 = \frac{(0.03 \, \text{M}) \times (100 \, \text{mL})}{0.5 \, \text{M}} = \frac{3}{0.5} = 6 \, \text{mL}
\]

So, you need **6 mL** of the 0.5M NaCl stock solution.

### 2. **Prepare 250 mL of 0.5M NaOH from stock solution of 10M NaOH.**

Again, use the dilution formula:

\[
C_1 V_1 = C_2 V_2
\]

Where:
- \(C_1\) = initial concentration (10 M)
- \(V_1\) = volume of the stock solution needed (in mL)
- \(C_2\) = final concentration (0.5 M)
- \(V_2\) = final volume (250 mL)

Substituting the values:

\[
(10 \, \text{M}) \times V_1 = (0.5 \, \text{M}) \times (250 \, \text{mL})
\]

\[
V_1 = \frac{(0.5 \, \text{M}) \times (250 \, \text{mL})}{10 \, \text{M}} = \frac{125}{10} = 12.5 \, \text{mL}
\]

So, you need **12.5 mL** of the 10M NaOH stock solution.

### 3. **How much water should be added to prepare 1L of 0.1M HCl from 2M HCl solution?**

Using the dilution formula:

\[
C_1 V_1 = C_2 V_2
\]

Where:
- \(C_1\) = initial concentration (2 M)
- \(V_1\) = volume of the stock solution needed (in L)
- \(C_2\) = final concentration (0.1 M)
- \(V_2\) = final volume (1 L)

Substituting the values:

\[
(2 \, \text{M}) \times V_1 = (0.1 \, \text{M}) \times (1 \, \text{L})
\]

\[
V_1 = \frac{(0.1 \, \text{M}) \times (1 \, \text{L})}{2 \, \text{M}} = \frac{0.1}{2} = 0.05 \, \text{L} = 50 \, \text{mL}
\]

To find out how much water to add, subtract the volume of the concentrated solution from the final volume:

\[
\text{Water to be added} = 1 \, \text{L} - 50 \, \text{mL} = 950 \, \text{mL}
\]

So, you should add **950 mL** of water.

### 4. **What is the universal solvent in preparing chemicals?**

The universal solvent is **water**.

---

Do you need further details or explanations on any of these problems? 

Here are some additional related questions you might explore:

1. What are the key differences between a solution and a suspension?
2. How would you prepare a buffer solution from a weak acid and its conjugate base?
3. What safety precautions should be taken when diluting strong acids like HCl?
4. How does temperature affect the solubility of NaCl in water?
5. How can the concentration of a solution be determined experimentally?

**Tip:** Always add acid to water, not water to acid, to avoid exothermic reactions that can cause splattering.

Learn how to calculate dilutions for NaCl and NaOH solutions in chemistry. Solve problems involving concentration, volume, and dilution formulas step-by-step. Suitable for advanced high school chemistry students.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation