The solutions for the currents in the circuit are:

\[
I_1 = \frac{185}{47} \, \text{A} \approx 3.94 \, \text{A}
\]
\[
I_2 = \frac{155}{47} \, \text{A} \approx 3.30 \, \text{A}
\]

So, the current \(I_1\) in the first mesh is approximately **3.94 A**, and the current \(I_2\) in the second mesh is approximately **3.30 A**.

Would you like to explore any specific aspects of this solution, or do you have further questions?

### Follow-up Questions:
1. How do the values of \(I_1\) and \(I_2\) change if the resistances are modified?
2. What happens to the current in the circuit if we reverse the polarity of one of the voltage sources?
3. How can we determine the power consumed by each resistor?
4. Can this method be applied to circuits with more than two meshes?
5. What is the impact of having different voltage sources in each mesh?
6. How would the solution change if a resistor were shared between the meshes?
7. Can you verify the solution using another method, such as nodal analysis?
8. What would the result be if one of the voltage sources were removed from the circuit?

### Tip:
When solving circuits with multiple meshes, it's crucial to carefully account for the direction of currents and the signs of voltage drops to avoid errors in the equations.

Explore how to calculate currents in electric circuits using mesh analysis. Learn the step-by-step process for solving currents in different meshes of a circuit with detailed examples and formulas. Suitable for advanced learners and professionals.

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