Light color In manufacturing, the mixing ratio of oxidant and color is 2:1. How much is needed colour and how much finished colour mass is obtained when 100 oxidants are applied ml?

Color needed A1 Question 15
ml

Ready-made color is obtained by: A2 Question 15
ml

Given that the mixing ratio of oxidant to color is 2:1, it means for every 2 parts of oxidant, 1 part of color is needed.

### Calculating the amount of color needed (A1):

If you have 100 ml of oxidant, and the ratio is 2:1:

\[
\text{Amount of color needed} = \frac{\text{Oxidant}}{2} = \frac{100 \, \text{ml}}{2} = 50 \, \text{ml}
\]

### Calculating the total amount of finished color mass (A2):

The total mass of the finished color will be the sum of the oxidant and the color:

\[
\text{Finished color mass} = \text{Oxidant} + \text{Color} = 100 \, \text{ml} + 50 \, \text{ml} = 150 \, \text{ml}
\]

### Summary:

- **A1:** 50 ml of color is needed.
- **A2:** The total finished color mass is 150 ml.

Would you like any further details or explanations?

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Here are some related questions to explore further:

1. What if the ratio were 3:1 instead of 2:1?
2. How would the calculations change if you started with 200 ml of oxidant?
3. How is the mixing ratio determined in manufacturing processes?
4. What would happen if the wrong ratio were used?
5. How can the final mass be measured in a real-life manufacturing process?
6. What other ingredients might affect the final color mass?
7. How does temperature affect the mixing of oxidants and colors?
8. What are common applications of such mixtures in industry?

**Tip:** When working with ratios, always ensure that units are consistent across all components before performing any calculations.

Learn how to calculate the amount of color needed and the total finished color mass using a ratio problem. Understand the application of ratios in manufacturing processes with a step-by-step solution. Suitable for Grades 6-8.

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