find the vlocity of a brick drooped after 5.0s using a∆t and a = -9.8m/s^2

To find the velocity of the brick after it has been dropped for 5.0 seconds, we can use the following kinematic equation:

\[
v = u + a\Delta t
\]

Where:
- \( v \) is the final velocity (what we're solving for),
- \( u \) is the initial velocity (since the brick is dropped, \( u = 0 \, \text{m/s} \)),
- \( a \) is the acceleration (given as \( -9.8 \, \text{m/s}^2 \), the acceleration due to gravity),
- \( \Delta t \) is the time (given as 5.0 seconds).

Now, substitute the known values:

\[
v = 0 + (-9.8 \, \text{m/s}^2)(5.0 \, \text{s})
\]

\[
v = -49.0 \, \text{m/s}
\]

Thus, the velocity of the brick after 5.0 seconds is **-49.0 m/s**. The negative sign indicates that the velocity is directed downwards.

Would you like more details, or do you have any questions?

Here are 5 related questions:
1. What is the velocity after 2.0 seconds?
2. How far does the brick fall after 5.0 seconds?
3. What would be the velocity if the brick was thrown upwards with an initial velocity of 10 m/s?
4. How does air resistance affect the velocity of the falling brick?
5. Can you use the same formula to find the velocity on other planets?

**Tip:** Always pay attention to the sign of acceleration when dealing with free fall problems; it indicates the direction of motion.

find the velocity of a brick dropped after 5.0s using Δt and a = -9.8m/s^2

Learn how to calculate the velocity of a brick dropped for 5 seconds using the kinematic equation v = u + aΔt. This problem involves free fall motion under gravity with acceleration -9.8 m/s². Suitable for high school physics students in Grades 9-12.

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