To find the resistance \( R \), we can use Ohm's Law, which states:

\[
R = \frac{V}{I}
\]

Given:
- Voltage \( V = 160 \text{ mV} = 160 \times 10^{-3} \text{ V} \)
- Current \( I = 8 \text{ μA} = 8 \times 10^{-6} \text{ A} \)

Now, let's calculate the resistance \( R \):

\[
R = \frac{160 \times 10^{-3} \text{ V}}{8 \times 10^{-6} \text{ A}}
\]

\[
R = \frac{160 \times 10^{-3}}{8 \times 10^{-6}} = 20 \times 10^3 \text{ Ω} = 20 \text{ kΩ}
\]

So, the resistance \( R \) is \( 20 \text{ kΩ} \).

Would you like more details or have any questions? 

Here are 5 related questions:
1. What happens to the resistance if the current is doubled?
2. How does changing the voltage affect the resistance in Ohm's Law?
3. Can you explain the significance of the units in Ohm's Law?
4. How would you calculate the power dissipation across the resistor?
5. What are the limitations of Ohm's Law in real-world circuits?

**Tip:** Always ensure that the units for voltage and current are consistent when applying Ohm's Law to avoid calculation errors.

Learn how to calculate resistance using Ohm's Law with specific values: Voltage (V) = 160 mV and Current (I) = 8 μA. Detailed step-by-step solution included.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation