To find the resistance \( R \) given the voltage \( V = 24 \, \text{V} \) and the current \( I = 800 \, \mu\text{A} \), we can use Ohm's Law:

\[
V = I \times R
\]

Rearranging the formula to solve for \( R \):

\[
R = \frac{V}{I}
\]

Now, substitute the given values into the equation. Remember to convert the current from microamperes to amperes:

\[
I = 800 \, \mu\text{A} = 800 \times 10^{-6} \, \text{A} = 0.0008 \, \text{A}
\]

So,

\[
R = \frac{24 \, \text{V}}{0.0008 \, \text{A}} = 30,000 \, \Omega
\]

Therefore, the resistance \( R \) is \( 30,000 \, \Omega \) or \( 30 \, \text{k}\Omega \).

Would you like more details or have any questions?

Here are five related questions to explore:

1. How would the resistance change if the current was halved?
2. What is the power dissipated by the resistor?
3. How would you calculate the resistance if the voltage was unknown?
4. Can Ohm's Law be applied to non-linear components?
5. What happens to the current if the resistance is doubled while maintaining the same voltage?

**Tip:** Always check the units when working with electrical equations; converting to base units ensures accuracy.

Learn how to calculate resistance (R) using Ohm's Law with a given voltage (V = 24V) and current (I = 800 μA). This problem involves basic electrical concepts and the application of Ohm's Law formula. Suitable for high school students.

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