# Homeworkify AI Homework Helper , Scan Solve Learn : Physics Demo

TLDRThis physics tutorial demonstrates the calculation of work done by a force. Given a force of 15N at a 45-degree angle to the horizontal and a displacement of 49 meters, the video explains how to find the horizontal component of the force and then uses it to calculate the work done as 520.89 Joules, which is further converted to 0.1244 kilo calories. The clear step-by-step process is aimed at helping students understand the concept of work in physics.

### Takeaways

- π The problem involves calculating the work done by a force in a physics scenario.
- π Given information includes a force of 15N, an angle of 45 degrees to the horizontal, and a distance of 49 meters.
- π The formula for work done is work = force x displacement x cos(angle), where 'angle' is the angle between the force and displacement.
- π The force's horizontal component is calculated using trigonometry: horizontal component = force x cos(angle).
- π The horizontal component of the force is found to be 10.61N by applying the formula with the given angle.
- βοΈ The work done by the force is then calculated using the horizontal component and the displacement.
- π The work done is 520.89 Joules, calculated by multiplying the horizontal force component by the displacement and cos(0 degrees).
- π To convert Joules to kilo calories (KCAL), divide the work in Joules by 4184.
- π The work done is equivalent to 0.1244 kilo calories after conversion.
- π€ The script encourages asking further physics questions for additional help.
- πΆ The transcript ends with a note of thanks and an offer for further assistance, signified by background music.

### Q & A

### What is the formula for work done by a force?

-The formula for work done by a force is work = force x displacement x cos(angle), where 'angle' is the angle between the force and the displacement.

### Why is it necessary to find the component of force in the direction of displacement?

-It is necessary to find the component of force in the direction of displacement because the force is not acting in the direction of displacement, and only the component of the force in the direction of displacement contributes to the work done.

### How is the horizontal component of force calculated using trigonometry?

-The horizontal component of force is calculated using the formula: horizontal component of force = force x cos(angle). In this case, it is 15 N x cos(45 degrees).

### What is the value of the horizontal component of force in the given problem?

-The value of the horizontal component of force in the given problem is 10.61 N.

### What is the work done by the force when the angle between the force and displacement is zero degrees?

-When the angle between the force and displacement is zero degrees, the work done by the force is simply the product of the horizontal component of force and the displacement, as cos(0 degrees) equals 1.

### What is the calculated work done by the force in the given problem?

-The calculated work done by the force in the given problem is 520.89 Joules.

### How can work in Joules be converted to kilo calories (KCAL)?

-Work in Joules can be converted to kilo calories (KCAL) by dividing the number of Joules by 4184, since 1 kilo calorie equals 4184 Joules.

### What is the equivalent of the work done in kilo calories (KCAL) for the given problem?

-The equivalent of the work done in kilo calories (KCAL) for the given problem is 0.1244 KCAL.

### Why is it important to understand the direction of the force relative to displacement when calculating work?

-Understanding the direction of the force relative to displacement is important because work is only done when a force causes a displacement in the direction of the force. The angle between the force and displacement affects the amount of work done.

### Can you provide an example of a situation where the work done by a force would be zero?

-An example of a situation where the work done by a force would be zero is when the force is perpendicular to the displacement, as the cosine of a 90-degree angle is zero.

### Outlines

### π Calculating Work Done by a Force

This paragraph discusses a physics problem involving the calculation of work done by a force. Given information includes a force of 15N at a 45-degree angle to the horizontal and a displacement of 49 meters. The formula for work done is introduced, which is work = force x displacement x cos(angle). The horizontal component of the force is calculated using trigonometry, resulting in 10.61N. The work done by the force is then determined by considering the horizontal component of the force and the displacement in the horizontal direction, yielding 520.89 Joules. The paragraph concludes with a conversion of the work done from Joules to kilo calories, using the conversion factor 1 kcal = 4184 J, resulting in 0.1244 kilo calories. The script invites further questions and provides a musical note at the end.

### Mindmap

### Keywords

### π‘Work

### π‘Force

### π‘Displacement

### π‘Angle

### π‘Component of Force

### π‘Trigonometry

### π‘Cosine

### π‘Joule

### π‘Kilocalorie

### π‘Conversion

### Highlights

Working on a physics problem step by step.

Identifying given information: Force = 15N, angle = 45 degrees, distance = 49 meters.

Objective: Find the work done by the force.

Using the formula for work: Work = Force x Displacement x cos(angle).

Force is not in the direction of displacement, need to find the horizontal component.

Calculating the horizontal component of force using trigonometry.

Horizontal component of force = 15N * cos(45 degrees) = 10.61N.

Applying the work formula with the horizontal force component.

Work done by the force when the angle between force and displacement is zero.

Calculating work: Work = 10.61N * 49m * cos(0 degrees) = 520.89 Joules.

Interpreting the result: 520.89 Joules of work done.

Converting work from Joules to kilo calories (KCAL).

Conversion factor: 1 KCAL = 4184 Joules.

Converting 520.89 Joules to KCAL: 520.89 / 4184 = 0.1244 KCAL.

Result: Work done equivalent to 0.1244 kilo calories.

Offering further assistance with physics questions.

## Casual Browsing

Need AI Homework Helper - how to use

2024-06-12 10:55:00

Gauth app - AI Homework helper - full overview

2024-06-20 09:50:00

Best AI Homework Helper: The Perfect AI for Students in 2023

2024-06-12 10:45:00

How To Use Gauth - Al Homework Helper #study #ai #how #gauthmath

2024-06-12 08:20:00

Learn to solve a system of equations using substitution

2024-06-12 23:15:00

Learn How To Solve Equations β Understand In 7 Minutes

2024-06-13 00:05:01