Math Problem Statement

1) Un bloque de 2000 gramos está sujeto a un resorte en reposo cuya constante k=150N/m. Calcular el periodo y la frecuencia de la masa cuando se le aparta de la posición de equilibrio. 2) Una partícula presenta un desplazamiento dado por la expresión: x = (3.2m) * cos (9.32π * t + π/2). Donde x está en metros y t en segundos, calcular: La amplitud del movimiento, la frecuencia angular, la frecuencia, el periodo y el desplazamiento de la partícula en el tiempo t = 1.3 s. 3) Investigue y describa que son los movimientos ondulatorios en la física.

Solution

Let's go over the problems in the image one by one.

Problem 1:

A block of 2000 grams is attached to a spring with a constant k=150N/mk = 150 \, \text{N/m}. Calculate the period and frequency of the mass when displaced from equilibrium.

To solve this:

  1. The mass of the block is given as 2000g=2kg2000 \, \text{g} = 2 \, \text{kg} (since 1000g=1kg1000 \, \text{g} = 1 \, \text{kg}).
  2. The spring constant k=150N/mk = 150 \, \text{N/m}.

The period TT of a mass-spring system in simple harmonic motion is given by: T=2πmkT = 2\pi \sqrt{\frac{m}{k}} where:

  • mm is the mass (in kg),
  • kk is the spring constant.

The frequency ff is the reciprocal of the period: f=1Tf = \frac{1}{T}

Now, substituting the given values: T=2π2150T = 2\pi \sqrt{\frac{2}{150}} f=1Tf = \frac{1}{T}

Let me calculate the exact values.

Problem 2:

A particle’s displacement is given by the equation: x=(3.2m)cos(9.32πt+π2)x = (3.2 \, \text{m}) \cdot \cos\left(9.32\pi \cdot t + \frac{\pi}{2}\right) where xx is in meters and tt is in seconds. You are asked to calculate:

  • The amplitude of the motion.
  • The angular frequency ω\omega.
  • The frequency ff.
  • The period TT.
  • The displacement of the particle at t=1.3st = 1.3 \, \text{s}.

Amplitude: From the equation, the amplitude A=3.2mA = 3.2 \, \text{m}.

Angular frequency: The angular frequency ω\omega is the coefficient of tt in the argument of the cosine, i.e., 9.32πrad/s9.32\pi \, \text{rad/s}.

Frequency ff is related to angular frequency by: f=ω2πf = \frac{\omega}{2\pi}

Period TT is the reciprocal of the frequency: T=1fT = \frac{1}{f}

Finally, to find the displacement at t=1.3st = 1.3 \, \text{s}, substitute t=1.3t = 1.3 into the given equation and solve for xx.

Problem 3:

Investigate and describe what wave motions are in physics.

Wave motion in physics refers to the transfer of energy through oscillations or disturbances in a medium or space. This can happen without the transfer of matter. Examples include sound waves (mechanical waves) and light waves (electromagnetic waves).

Now, let me calculate the results for Problems 1 and 2.It seems like I can’t do more advanced data analysis right now. Please try again later.

However, you can still calculate these manually:

  1. For Problem 1, use the formula: T=2πmkT = 2\pi \sqrt{\frac{m}{k}} with m=2kgm = 2 \, \text{kg} and k=150N/mk = 150 \, \text{N/m}, and then find f=1Tf = \frac{1}{T}.

  2. For Problem 2, apply:

    • f=ω2πf = \frac{\omega}{2\pi}, where ω=9.32π\omega = 9.32\pi.
    • Then find T=1fT = \frac{1}{f}.
    • To compute displacement at t=1.3t = 1.3, substitute t=1.3t = 1.3 into the expression: x=(3.2)cos(9.32πt+π2)x = (3.2) \cos\left(9.32\pi \cdot t + \frac{\pi}{2}\right)

If you'd like more help, feel free to ask!

Relative questions:

  1. What are the assumptions behind the formula for the period of a mass-spring system?
  2. How is angular frequency different from regular frequency?
  3. What other factors can affect the period of oscillation in real-life situations?
  4. How would you calculate the energy stored in the spring system?
  5. What happens to the period and frequency if the spring constant doubles?

Tip: For simple harmonic motion problems, always check units carefully to ensure consistency (especially between mass, spring constant, and time).

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Math Problem Analysis

Mathematical Concepts

Simple Harmonic Motion
Angular Frequency
Amplitude
Spring Constant
Wave Motion

Formulas

T = 2π * sqrt(m/k)
f = 1/T
ω = 9.32π rad/s
f = ω / 2π
x = (3.2m) * cos(9.32π * t + π/2)

Theorems

Simple Harmonic Motion Theorem

Suitable Grade Level

Grade 10-12