Math Problem Statement

Explain why we put 7 as M

Explain why we put 7 as M.

Solution

The question provided involves a spring system where a spring with a spring constant k=700N/mk = 700 \, \text{N/m} is hanging vertically, and a mass m=0.05kgm = 0.05 \, \text{kg} is attached to it. Here's the explanation for why 7 might appear as MM in similar examples or cases:


Understanding the Setup:

  1. Spring Constant kk: The spring constant k=700N/mk = 700 \, \text{N/m} determines the stiffness of the spring.

  2. Mass mm: The attached mass is m=0.05kgm = 0.05 \, \text{kg}, and when released, the mass will oscillate in simple harmonic motion (neglecting air resistance).

  3. Gravitational Force FgF_g: The weight of the mass, which stretches the spring initially, is: Fg=mgF_g = mg where g=9.8m/s2g = 9.8 \, \text{m/s}^2. Substituting m=0.05kgm = 0.05 \, \text{kg}: Fg=0.05×9.8=0.49NF_g = 0.05 \times 9.8 = 0.49 \, \text{N}

  4. Spring Displacement xx: The equilibrium displacement xx of the spring due to the weight is calculated using Hooke's Law: F=kx    x=FgkF = kx \quad \implies \quad x = \frac{F_g}{k} Substituting the values Fg=0.49NF_g = 0.49 \, \text{N} and k=700N/mk = 700 \, \text{N/m}: x=0.49700=0.0007m.x = \frac{0.49}{700} = 0.0007 \, \text{m}.


Why 7 (Possibility):

If you see 7 used as a mass or value, it could arise from:

  1. Rounded Representation:
    Sometimes, values can be simplified or approximated. For example:

    • If the problem involved m=7kgm = 7 \, \text{kg} as an example in a prior problem.
    • 0.05kg0.05 \, \text{kg} could be misread or scaled improperly.
  2. Conversion Errors:
    Misinterpretations between units (like grams to kilograms or force and mass units) could introduce a "7" somewhere.

  3. Spring Motion Calculation:
    If we analyze the motion, quantities like amplitude, energy, or time period could involve values around the number 7 in an earlier result.


If you provide more context or clarify where "7" comes up in your calculations, I can resolve this further. Does this explanation align with what you're asking?


Related Questions:

  1. How do you calculate the equilibrium position of the spring under the weight of the mass?
  2. What is the equation of motion for the mass attached to the spring?
  3. How is the time period of oscillation determined for a spring-mass system?
  4. What happens if air resistance is considered in this scenario?
  5. How do you calculate the total mechanical energy of the oscillating system?

Tip: Always ensure consistent units when dealing with forces, masses, and spring constants (e.g., N, kg, m). Misconversions can introduce unexpected values.

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Math Problem Analysis

Mathematical Concepts

Simple Harmonic Motion (SHM)
Hooke's Law
Equilibrium position in spring systems

Formulas

F = kx
F = mg
x = F / k
T = 2π√(m/k)

Theorems

Hooke's Law
Newton's Second Law of Motion
Time period of a spring-mass system

Suitable Grade Level

Grades 11-12