. A house costs 36% more today than when it was built. If the cost of the house today is $333 200, find its cost when it was built.

Let the cost of the house when it was built be denoted by $ x $.

According to the problem, the cost of the house today is 36% more than when it was built. This can be expressed mathematically as:

\[
x + 0.36x = 333,200
\]

This simplifies to:

\[
1.36x = 333,200
\]

Now, to find $ x $, we divide both sides of the equation by 1.36:

\[
x = \frac{333,200}{1.36}
\]

\[
x \approx 244,852.94
\]

So, the cost of the house when it was built was approximately **$244,852.94**.

Would you like more details or have any questions?

Here are 5 related questions:
1. If the house had increased by 50% instead of 36%, what would the original cost be?
2. What would be the value of the house if it increased by 25% from the original cost of $244,852.94?
3. If the house decreases in value by 10% next year, what will its new value be?
4. How much did the value of the house increase in dollars from when it was built to today?
5. If the rate of increase was 4% annually, how many years did it take to reach the current price?

**Tip:** When dealing with percentage increases, it can be helpful to factor in the original value to make calculations easier.

Discover how to find the original cost of a house given a 36% increase to $333,200. Learn the step-by-step solution involving percentage increase formulas and linear equations. Suitable for Grades 7-9.

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