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The problem asks to calculate \( \log 70 \) given that \( \log 7 = 0.8451 \).

We can solve this by using the property of logarithms that allows us to break down \( \log 70 \) as:

\[
\log 70 = \log (7 \times 10) = \log 7 + \log 10
\]

We know from the problem that \( \log 7 = 0.8451 \), and we also know that \( \log 10 = 1 \), since the logarithm of 10 in base 10 is always 1. Therefore:

\[
\log 70 = 0.8451 + 1 = 1.8451
\]

So, the value of \( \log 70 \) is approximately **1.8451**.

Would you like further details on this solution, or do you have any questions?

Here are 5 related questions for further practice:
1. How would you calculate \( \log 700 \) given \( \log 7 = 0.8451 \)?
2. What is the value of \( \log 0.7 \) using properties of logarithms?
3. Can you find \( \log 14 \) using the same logarithmic rules?
4. If \( \log 7 = 0.8451 \), what is \( \log 49 \)?
5. How would you use logarithms to simplify \( \log 0.07 \)?

**Tip**: Remember, logarithms transform products into sums, quotients into differences, and powers into products to make complex calculations simpler.

Learn how to calculate log 70 using the logarithmic property log(a * b) = log a + log b, given that log 7 = 0.8451. This problem covers logarithmic concepts and properties, suitable for students in Grades 9-11.

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