The problem asks to calculate $\log 70$ given that $\log 7 = 0.8451$.

We can solve this by using the property of logarithms that allows us to break down $\log 70$ as:

$\log 70 = \log (7 \times 10) = \log 7 + \log 10$

We know from the problem that $\log 7 = 0.8451$, and we also know that $\log 10 = 1$, since the logarithm of 10 in base 10 is always 1. Therefore:

$\log 70 = 0.8451 + 1 = 1.8451$

So, the value of $\log 70$ is approximately 1.8451.

Would you like further details on this solution, or do you have any questions?

Here are 5 related questions for further practice:

1. How would you calculate $\log 700$ given $\log 7 = 0.8451$?
2. What is the value of $\log 0.7$ using properties of logarithms?
3. Can you find $\log 14$ using the same logarithmic rules?
4. If $\log 7 = 0.8451$, what is $\log 49$?
5. How would you use logarithms to simplify $\log 0.07$?

Tip: Remember, logarithms transform products into sums, quotients into differences, and powers into products to make complex calculations simpler.