Math Problem Statement

Evaluate log base 0.7 of 11.8 using the change-of-base property and a calculator.

Solution

The task in the image involves using the change-of-base formula to evaluate the expression log0.7(11.8)\log_{0.7}(11.8). Let me guide you through the steps for solving it.

Step 1: Change-of-Base Formula

The change-of-base formula for logarithms is: logb(a)=ln(a)ln(b)\log_b(a) = \frac{\ln(a)}{\ln(b)} where ln\ln is the natural logarithm (logarithm base ee).

Step 2: Apply the Formula

For the expression log0.7(11.8)\log_{0.7}(11.8), we use the change-of-base formula: log0.7(11.8)=ln(11.8)ln(0.7)\log_{0.7}(11.8) = \frac{\ln(11.8)}{\ln(0.7)}

Step 3: Calculate Each Natural Logarithm

  1. ln(11.8)2.4681\ln(11.8) \approx 2.4681
  2. ln(0.7)0.3567\ln(0.7) \approx -0.3567

Step 4: Division

Now, divide the two results: 2.46810.35676.9188\frac{2.4681}{-0.3567} \approx -6.9188

So, log0.7(11.8)6.9188\log_{0.7}(11.8) \approx -6.9188.

This value is rounded to four decimal places as required.

Would you like more details on this, or do you have any questions? Here are some related questions you might find helpful:

  1. How does the change-of-base formula work in general?
  2. What is the significance of the natural logarithm in mathematics?
  3. Can you explain why ln(0.7)\ln(0.7) is negative?
  4. How would the result change if the base were greater than 1?
  5. What are some real-life applications of logarithms with bases less than 1?

Tip: When calculating logarithms with bases less than 1, the result is often negative, as seen here.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Change-of-Base Formula

Formulas

log_b(a) = ln(a) / ln(b)

Theorems

Change-of-Base Theorem

Suitable Grade Level

Grades 9-12