Math Problem Statement

for part b the question is 7^log7x

Solution

To simplify the expression 7log7x7^{\log_7 x}, we can use a fundamental property of logarithms and exponents.

Property:

If alogab=ba^{\log_a b} = b, where aa and bb are positive numbers, then the expression simplifies directly to bb.

Applying this to your problem:

Given: 7log7x7^{\log_7 x}

By the property mentioned above: 7log7x=x7^{\log_7 x} = x

Thus, 7log7x7^{\log_7 x} simplifies to xx.

Final answer:

7log7x=x7^{\log_7 x} = x

Would you like more details or examples about logarithms and exponents?

Here are 5 related questions to help expand on this concept:

  1. What is the inverse relationship between exponents and logarithms?
  2. How can we solve for xx when given an equation like 3log3x=813^{\log_3 x} = 81?
  3. How does the property alogax=xa^{\log_a x} = x apply to other bases like 10 or ee?
  4. What would happen if we had 7log7(2x)7^{\log_7 (2x)}?
  5. Can this property be applied in cases where the base and the logarithm are different?

Tip: Understanding the relationship between exponents and logarithms can make simplifying complex expressions much easier.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponents

Formulas

a^log_a(b) = b

Theorems

Exponential and Logarithmic Properties

Suitable Grade Level

Grades 9-11