An insulin drip is mixed as 225.0 units in 250.0 mL Normal Saline (NS). Calculate the drip rate in mL/h needed to deliver 4.00 units/h?

To calculate the drip rate in mL/h needed to deliver 4.00 units/h of insulin, you can use the following steps:

### Step 1: Determine the concentration of insulin in the solution.
- **Insulin concentration** = \(\frac{\text{Total units of insulin}}{\text{Total volume of solution}}\)

\[
\text{Concentration} = \frac{225.0 \text{ units}}{250.0 \text{ mL}} = 0.9 \text{ units/mL}
\]

### Step 2: Calculate the drip rate in mL/h.
- **Drip rate** = \(\frac{\text{Desired units per hour}}{\text{Concentration of insulin}}\)

\[
\text{Drip rate} = \frac{4.00 \text{ units/h}}{0.9 \text{ units/mL}} \approx 4.44 \text{ mL/h}
\]

So, the drip rate needed is approximately **4.44 mL/h**.

Would you like more details or have any questions?

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Here are five related questions you might find useful:
1. How would the drip rate change if the concentration of insulin was increased?
2. What is the significance of maintaining an accurate drip rate for insulin?
3. How would you calculate the time required to administer a certain amount of insulin at this rate?
4. How does the volume of Normal Saline used affect the concentration of the solution?
5. How would you adjust the drip rate if the desired delivery rate was 6.00 units/h?

**Tip:** Always double-check your calculations, especially when dealing with medication dosages, as errors can have significant consequences.

Learn how to calculate the drip rate needed to deliver 4.00 units/h of insulin when mixed as 225.0 units in 250.0 mL Normal Saline. This problem covers key concepts like concentration calculation and unit conversion, suitable for students in Grades 10-12.

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