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To solve this problem, we need to calculate the energy transferred by a cooker with a power rating of 2000 W (Watts) over half an hour. The energy can be calculated using the formula:

\[
E = P \times t
\]

Where:
- \( E \) is the energy (in joules, J),
- \( P \) is the power (in watts, W),
- \( t \) is the time (in seconds, s).

First, we convert half an hour into seconds:
\[
\text{Time in seconds} = 0.5 \times 60 \times 60 = 1800 \, \text{seconds}
\]

Now, we calculate the energy in joules:
\[
E = 2000 \, \text{W} \times 1800 \, \text{s} = 3,600,000 \, \text{J}
\]

Finally, convert joules to kilojoules:
\[
1 \, \text{kJ} = 1000 \, \text{J}
\]
\[
E = \frac{3,600,000}{1000} = 3600 \, \text{kJ}
\]

So, the energy transferred is **3600 kJ**.

Would you like more details or have any questions?

Here are 5 related questions to expand on this:
1. How does the power rating of a device affect the amount of energy it transfers?
2. What would the energy transfer be if the cooker ran for 1 hour instead?
3. How would you convert kilowatt-hours to kilojoules?
4. What is the relationship between time, power, and energy in electrical devices?
5. How does energy consumption change if the power rating is halved but the time is doubled?

**Tip:** Always check the units in power and time before calculating energy to avoid errors.

How much energy is transferred by a cooker with a power rating of 2000 W in half an hour? Give your answer in kilojoules (kJ).

Learn how to calculate the energy transferred by a 2000W cooker running for half an hour. This solution covers power, time conversion, and energy calculation in kilojoules (kJ). Suitable for students in Grades 8-10.

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