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To solve the problem, we need to calculate the energy transferred by the 3 kW kettle, which boils 500 cm³ of water in 3 minutes.

### Step-by-Step Solution:

1. **Power (P):** The kettle's power is given as 3 kW, which is 3000 watts (since 1 kW = 1000 W).

2. **Time (t):** The time taken to boil the water is 3 minutes. We convert this into seconds:
   \[
   t = 3 \, \text{minutes} = 3 \times 60 = 180 \, \text{seconds}
   \]

3. **Energy Formula:** The energy \( E \) transferred is calculated using the formula:
   \[
   E = P \times t
   \]
   Substituting the known values:
   \[
   E = 3000 \, \text{W} \times 180 \, \text{s} = 540,000 \, \text{J} = 540 \, \text{kJ}
   \]

So, the energy transferred by the 3 kW kettle while boiling the water is **540 kJ**.

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### Relative Questions:
1. How is the power of a device related to the energy it transfers?
2. Why do we convert time into seconds when calculating energy?
3. How can the efficiency of the kettle affect the energy calculation?
4. What is the significance of the unit "kW" in electrical appliances?
5. How would the energy change if the kettle took more time to boil the same volume of water?

**Tip:** Always ensure that the units of time and power are consistent when calculating energy; otherwise, the result will be inaccurate.

How much energy is transferred (in kilojoules) by the 3 kW kettle while it boils 500 cm³ of water in 3 minutes?

Learn how to calculate the energy transferred by a 3 kW kettle boiling 500 cm³ of water in 3 minutes. This problem explores energy transfer concepts using the formula Energy = Power × Time. Suitable for Grades 7-9.

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