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To solve this problem, we need to calculate the energy transferred by the 2.2 kW kettle while it boils the water in 3.5 minutes.

### Formula to use:
Energy \( E = \text{Power} \times \text{Time} \)

1. **Power (P)**: 2.2 kW (kilowatts), which is \( 2200 \, \text{W} \) (watts).
2. **Time (t)**: 3.5 minutes, which we convert into seconds:  
   \( 3.5 \times 60 = 210 \, \text{seconds} \).

Now, plug the values into the formula:
\[
E = 2200 \, \text{W} \times 210 \, \text{s} = 462,000 \, \text{J} \, (\text{joules})
\]

3. **Convert joules to kilojoules**:  
\( 462,000 \, \text{J} = 462 \, \text{kJ} \).

### Final Answer:
The energy transferred by the 2.2 kW kettle while it boils the water is **462 kJ**.

Would you like more details or have any questions?

Here are 5 related questions to expand your understanding:
1. How would the energy change if the power rating was different?
2. How do you convert energy from joules to kilojoules?
3. Why is it necessary to convert minutes to seconds in this calculation?
4. What is the energy transferred by the 3 kW kettle?
5. How does boiling time affect the total energy transferred?

**Tip:** Always ensure you convert units correctly, especially when working with time (minutes to seconds) and power (kW to W).

How much energy is transferred (in kilojoules, kJ) by the 2.2 kW kettle while it boils the water?

Learn how to calculate the energy transferred by a 2.2 kW kettle while boiling water for 3.5 minutes. This problem explores the relationship between power, time, and energy, using a step-by-step approach to convert watts to joules and joules to kilojoules. Suitable for middle school students.

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