David crawls 4ft south and then 6ft east. What is his distance and displacement?

David's **distance** and **displacement** can be calculated as follows:

### Distance:
The total distance David crawled is simply the sum of the distances he covered:
- He crawled 4 feet south and 6 feet east.

\[
\text{Distance} = 4 \, \text{ft} + 6 \, \text{ft} = 10 \, \text{ft}
\]

### Displacement:
Displacement is the straight-line distance between his starting and ending points, which forms the hypotenuse of a right triangle. Using the Pythagorean theorem:

\[
\text{Displacement} = \sqrt{(4 \, \text{ft})^2 + (6 \, \text{ft})^2}
\]

\[
\text{Displacement} = \sqrt{16 + 36} = \sqrt{52} \approx 7.21 \, \text{ft}
\]

Thus:
- **Distance** = 10 feet
- **Displacement** ≈ 7.21 feet (in a direction somewhere southeast).

Would you like more details or have any questions about this?

Here are 5 related questions:
1. How do you calculate the angle of the displacement?
2. What if David crawled in a different direction, say west?
3. Can the displacement ever be greater than the distance?
4. How does the Pythagorean theorem work in 3D?
5. What is the concept of displacement in physics?

**Tip:** Displacement always considers direction, making it a vector quantity, while distance is just a scalar value.

Find out how to calculate the total distance and the displacement when David crawls 4ft south and 6ft east. This solution uses the Pythagorean theorem to determine displacement, offering a clear explanation suitable for students in Grades 6-8.

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