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The problem describes a person's movement: 4 km north, 3 km east, and 1 km down. To find the displacement, we can treat this as a 3D vector problem and apply the Pythagorean theorem in three dimensions.

The formula for displacement is:
\[
\text{Displacement} = \sqrt{(x^2 + y^2 + z^2)}
\]
where:
- \(x = 4 \, \text{km} \) (north)
- \(y = 3 \, \text{km} \) (east)
- \(z = 1 \, \text{km} \) (down)

\[
\text{Displacement} = \sqrt{(4^2 + 3^2 + 1^2)} = \sqrt{(16 + 9 + 1)} = \sqrt{26}
\]

Therefore, the displacement is \( \sqrt{26} \, \text{km} \), corresponding to option **B**.

If a person goes 4 km in north, 3 km in east, and then 1 km down, what is the displacement?

Learn how to calculate the displacement of a person who moves 4 km north, 3 km east, and 1 km down. This problem utilizes vector geometry and applies the Pythagorean Theorem in 3D to find the solution, suitable for Grades 9-12.

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