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The question asks how many grams of dextrose are needed to prepare 1 liter (L) of a 25% solution.

In a 25% dextrose solution, 25% of the total volume is dextrose. This means that in every 100 milliliters (mL) of solution, 25 grams (g) of dextrose are present.

Since the prescriber orders 1 liter (1000 mL) of solution:

\[
\text{Grams of dextrose} = 25\% \times 1000 \, \text{mL} = 0.25 \times 1000 = 250 \, \text{g}.
\]

Thus, the correct answer is **D. 250 g**.

Would you like more details or have any other questions?

Here are five related questions:
1. How do you prepare a 10% dextrose solution?
2. What is the difference between volume/volume and weight/volume percentages in solutions?
3. How do you convert between molarity and percentage concentration?
4. What is the process of diluting a concentrated solution to a lower concentration?
5. Why are specific concentrations used in medical prescriptions?

**Tip:** Always verify if the concentration refers to weight/volume or volume/volume, especially when dealing with liquid solutions.

A prescriber orders 1 L of dextrose 25% solution. How many grams of dextrose will you need to prepare 1 L of a 25% solution?

Learn how to calculate the grams of dextrose required to prepare a 1-liter 25% dextrose solution. The problem involves understanding solution concentrations and percentages, making it suitable for students in Grades 9-12.

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