I bought 200 cases of coffee.  One case = 24 pounds.  Each case costs $66.50.   How much is the coffee per pound?

To find the cost of the coffee per pound, you need to determine the total number of pounds and the total cost, then divide the total cost by the total pounds.

1. Each case weighs 24 pounds, so for 200 cases, the total weight is:

\[
200 \times 24 = 4800 \, \text{pounds}
\]

2. Each case costs $66.50, so for 200 cases, the total cost is:

\[
200 \times 66.50 = 13300 \, \text{dollars}
\]

3. Now, divide the total cost by the total pounds to find the cost per pound:

\[
\frac{13300}{4800} \approx 2.77 \, \text{dollars per pound}
\]

So, the coffee costs approximately **$2.77 per pound**.

Would you like further details or have any questions?

---

Here are 5 related questions to explore:
1. What would be the total cost for 500 pounds of coffee?
2. If the price per case increased by 10%, what would the new cost per pound be?
3. How much would it cost to buy 10 more cases?
4. What is the cost of coffee per ounce (there are 16 ounces in a pound)?
5. If a customer buys 50 pounds of coffee, how much would it cost them?

**Tip:** To easily find the price per unit, divide the total cost by the total quantity.

I bought 200 cases of coffee. One case = 24 pounds. Each case costs $66.50. How much is the coffee per pound?

Find out how to calculate the cost per pound of coffee when buying 200 cases, each weighing 24 pounds and costing $66.50. Learn step-by-step how to determine unit price using multiplication and division. Suitable for students in Grades 5-7.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation