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The problem asks to calculate the total revenue a bakery makes from selling cakes and cookies using the revenue function \( R(x, y) = 200x + 50y \), where \( x \) represents the number of cakes sold, and \( y \) represents the number of cookies sold.

We are given that:
- The bakery sold 8 cakes, so \( x = 8 \).
- The bakery sold 15 cookies, so \( y = 15 \).

Substituting these values into the revenue function:

\[
R(8, 15) = 200(8) + 50(15)
\]

Now, let's calculate the total revenue:

\[
R(8, 15) = 1600 + 750 = 2350 \, \text{pesos}
\]

So, the bakery made **2,350 pesos** in revenue that day.

Would you like further details on this? Here are some related questions you might find interesting:

1. What if the bakery sold 12 cakes and 10 cookies?
2. How would the revenue change if the price per cake increased to 250 pesos?
3. What is the formula for revenue if the bakery also sold drinks for 30 pesos each?
4. How does the revenue change if the number of cookies sold doubles?
5. If the bakery had a daily target revenue of 3000 pesos, how many more cookies would they need to sell?

**Tip:** Always double-check your units (e.g., pesos) to ensure accuracy when solving word problems involving money.

A local bakery sells cakes and cookies. The total revenue R (in pesos) from selling x cakes and y cookies is given by the function R(x,y) = 200x + 50y, where cakes are sold for 200 pesos each and cookies for 50 pesos each. If the bakery sold 8 cakes and 15 cookies in one day, how much revenue did they make that day?

Learn how to calculate the total revenue of a bakery using the linear equation R(x, y) = 200x + 50y. This problem covers key algebra concepts, such as the use of linear equations for calculating revenue. The bakery sold 8 cakes and 15 cookies in one day, making a total revenue of 2,350 pesos.

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