Math Problem Statement
Solution
To solve the problem of showing that the function has a root in the interval , and then using the Bisection method to approximate the root to within , let's proceed step by step.
1. Confirming the Existence of a Root in the Interval
We can confirm that a root exists in the interval using the Intermediate Value Theorem (IVT), which states that if a continuous function changes signs over an interval , then there exists at least one root in that interval.
-
First, compute :
-
Now, compute :
Since and , and the function changes sign from negative to positive in this interval, there must be at least one root between and , as per the IVT.
2. Bisection Method to Approximate the Root
The Bisection method is an iterative process that repeatedly halves the interval to converge to the root. To achieve accuracy within , we will perform the following steps:
- Initial Interval:
- Tolerance:
Step-by-Step Iteration:
- Compute the midpoint .
- Evaluate :
- Since , the root must lie in the interval .
Now I will implement the full bisection process and calculate the root to the desired accuracy of . Let me compute this for you.Using the Bisection method, the root of the equation in the interval is approximately to an accuracy of . This result was obtained after 9 iterations.
Would you like further details on any part of the process or have any other questions?
Here are some related questions to deepen your understanding:
- What are the conditions for applying the Bisection method?
- How does the Intermediate Value Theorem guarantee the existence of a root?
- What happens if and are both positive or negative in the interval?
- How can you improve the convergence rate of the Bisection method?
- Can you apply the Newton-Raphson method to this problem for faster convergence?
Tip: When using the Bisection method, the number of iterations required to reach a given accuracy depends on the width of the interval and the desired tolerance, following the relation .
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Calculus
Root Finding
Bisection Method
Intermediate Value Theorem
Formulas
f(x) = x^3 + 4x^2 - 10
Midpoint Formula: m = (a + b) / 2
Theorems
Intermediate Value Theorem
Suitable Grade Level
Undergraduate level (first-year calculus)
Related Recommendation
Solve f(x) = x^3 + 4x^2 - 10 Using Bisection Method
Root Approximation Using the Bisection Method for f(x) = x^3 + 4x^2 - 10
Number of Iterations to Solve f(x) = x^3 + 4x^2 - 10 = 0 Using Bisection Method
Approximate the Real Zero of f(x) = x^3 - 2x^2 - 8x - 3 using the Bisection Method
Solving Polynomial Roots Using the Bisection Method: Step-by-Step Guide