Math Problem Statement

me das en una tabla el resultado

Hallar una aproximación x* de la única raíz real de la ecuación f(x) = 0, utilizando el método de bisección con un error inferior a 10^-2.

Solution

The problem asks to approximate the unique real root xx^* of the function f(x)=x3+4x210f(x) = x^3 + 4x^2 - 10 using the Bisection Method with an error smaller than 10210^{-2}.

The Bisection Method works as follows:

  1. You choose an initial interval [a,b][a, b] such that f(a)f(a) and f(b)f(b) have opposite signs (i.e., f(a)f(b)<0f(a) \cdot f(b) < 0, guaranteeing a root in that interval).
  2. You compute the midpoint c=a+b2c = \frac{a + b}{2} and evaluate f(c)f(c).
  3. Based on the sign of f(c)f(c), you choose the subinterval [a,c][a, c] or [c,b][c, b] where the root lies.
  4. This process is repeated until the error ba|b - a| is less than the desired tolerance (in this case, 10210^{-2}).

Let's start by identifying an interval where the sign changes for f(x)f(x).

Step 1: Define the function

f(x)=x3+4x210f(x) = x^3 + 4x^2 - 10

We will now find an initial interval [a,b][a, b] and calculate the root step by step using the Bisection Method.Here is a table summarizing the results of applying the Bisection Method to approximate the root of the equation f(x)=x3+4x210=0f(x) = x^3 + 4x^2 - 10 = 0, with an error less than 10210^{-2}:

Iterationaabbc=a+b2c = \frac{a+b}{2}f(a)f(a)f(b)f(b)f(c)f(c)bab - a
11.00002.00001.5000-5.000014.00002.37501.0000
21.00001.50001.2500-5.00002.3750-1.79690.5000
31.25001.50001.3750-1.79692.37500.16210.2500
41.25001.37501.3125-1.79690.1621-0.84840.1250
51.31251.37501.3438-0.84840.1621-0.35100.0625
61.34381.37501.3594-0.35100.1621-0.09640.0313
71.35941.37501.3672-0.09640.16210.03240.0156
81.35941.36721.3633-0.09640.0324-0.03210.0078

The root approximation after 8 iterations is x1.3633x^* \approx 1.3633 with an error less than 10210^{-2}.

Would you like a more detailed explanation of the method or its steps?

Here are 5 follow-up questions you might find useful:

  1. How does the Bisection Method compare to other numerical methods like Newton's method?
  2. Can the Bisection Method be used to find multiple roots of a function?
  3. What is the significance of the sign change in the Bisection Method?
  4. How can you ensure the Bisection Method converges to the correct root?
  5. What are some limitations of the Bisection Method in practical applications?

Tip: Always check the function for continuity and sign changes before applying the Bisection Method!

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Math Problem Analysis

Mathematical Concepts

Numerical Methods
Root Finding
Bisection Method

Formulas

f(x) = x^3 + 4x^2 - 10
Bisection formula: c = (a + b) / 2
Error condition: |b - a| < tolerance

Theorems

Intermediate Value Theorem
Bisection Method Convergence

Suitable Grade Level

College level