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The problem asks to find the area of a rectangular soccer field with the given dimensions:

- Length: \( (7a - 3) \) yards
- Width: \( 2a \) yards

### Step-by-step solution:

1. **Formula for the area of a rectangle**:  
   The area \( A \) of a rectangle is given by the product of its length and width:
   \[
   A = \text{Length} \times \text{Width}
   \]

2. **Substitute the given values**:  
   The length is \( (7a - 3) \) and the width is \( 2a \). So the area is:
   \[
   A = (7a - 3) \times 2a
   \]

3. **Distribute the \( 2a \) to both terms in the parentheses**:
   \[
   A = 2a \times 7a - 2a \times 3
   \]
   This gives:
   \[
   A = 14a^2 - 6a
   \]

4. **Final expression**:  
   The area of the rectangular field is \( 14a^2 - 6a \) square yards.

### Correct answer:
The correct answer matches the second option:  
\[
\boxed{(14a^2 - 6a) \text{ yards}}
\]

Let me know if you have any questions or would like further details!

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Here are 5 related questions:
1. How do you factor a quadratic expression like \( 14a^2 - 6a \)?
2. What are the properties of a rectangle that help calculate its area?
3. How would the area change if the length and width of the field doubled?
4. Can you find the area if specific values for \( a \) were given?
5. How does the distributive property work when multiplying binomials?

**Tip:** When multiplying a binomial by a monomial, apply the distributive property by multiplying the monomial with each term inside the binomial.

Find the area of a rectangular soccer field with a length of (7a - 3) yards and a width of 2a yards.

Learn how to calculate the area of a rectangular soccer field using algebraic expressions. This problem involves the application of the distributive property and area formulas, suitable for students in Grades 6-8.

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