The problem is asking about a rectangular football field where the length is double the width, and the total perimeter is 72 meters. We need to calculate the dimensions of the field (length and width), its total area, and how much space the field covers.

Step 1: Relationship between Length and Width

Let's denote the width by $x$, and since the length is double the width, the length will be $2x$.

Step 2: Perimeter Formula

The perimeter $P$ of a rectangle is given by:

$P = 2(\text{length} + \text{width})$

Substitute the length and width:

$72 = 2(2x + x)$

Step 3: Solve for $x$

Simplifying the equation:

$72 = 2(3x)$

$72 = 6x$

$x = \frac{72}{6} = 12$

So, the width $x$ is 12 meters, and the length $2x$ is:

$2x = 2 \times 12 = 24 \text{ meters}$

Step 4: Calculate the Area

The area $A$ of a rectangle is given by:

$A = \text{length} \times \text{width}$

$A = 24 \times 12 = 288 \text{ square meters}$

Final Answer:

• Length: 24 meters
• Width: 12 meters
• Perimeter: Already given as 72 meters
• Area: 288 square meters

Do you need more details, or have any other questions?

Here are some related questions:

1. How do you calculate the perimeter if you know both dimensions?
2. What is the formula for the area of other shapes like triangles or circles?
3. How would the problem change if the length was 3 times the width?
4. What units are commonly used for measuring area?
5. How can you verify that the dimensions you find are correct?

Tip: Always double-check the dimensions by plugging them back into the perimeter and area formulas to verify your results!