To write the equation of a line in point-slope form, we use the formula:

$y - y_1 = m(x - x_1)$

where:

• $(x_1, y_1)$ is a point on the line,
• $m$ is the slope of the line.

Given:

• The point $(-8, 5)$,
• The slope $m = -\frac{3}{4}$,

Substituting these values into the point-slope form:

$y - 5 = -\frac{3}{4}(x + 8)$

This is the equation of the line in point-slope form.

Would you like to go into more detail about how to convert this into slope-intercept form or explore a related topic?

Here are five questions related to this concept:

1. How do you convert the point-slope form to the slope-intercept form?
2. What is the slope-intercept form of the equation derived above?
3. How do you find the equation of a line parallel to this line?
4. What is the y-intercept of the line described by this equation?
5. How can you determine the x-intercept of this line?

Tip: The point-slope form is particularly useful when you know a point on the line and the slope, as it directly incorporates this information into the equation.