Math Problem Statement

X and Y can complete a work in 12 days together. After working 4 days together, Y left the job and a third person Z, whose efficiency is 5/3 of efficiency of X, joins the work. The whole work is completed in 8 days. In how many days, Y can complete the whole work alone?

Solution

Let the total work be denoted as WW, and the work done by X and Y together in one day is their combined efficiency, which is W12\frac{W}{12}.

Step 1: Work done by X and Y together in 4 days

In 4 days, X and Y together will complete: Work completed in 4 days=4×W12=W3\text{Work completed in 4 days} = 4 \times \frac{W}{12} = \frac{W}{3} This means that 2W3\frac{2W}{3} of the work remains after Y leaves the job.

Step 2: Work done by X and Z in the remaining 8 days

Z joins the work, and the efficiency of Z is 53\frac{5}{3} times the efficiency of X. Let the efficiency of X be EXE_X. Then the efficiency of Z is: EZ=53EXE_Z = \frac{5}{3} E_X The combined efficiency of X and Z is: EX+EZ=EX+53EX=83EXE_X + E_Z = E_X + \frac{5}{3} E_X = \frac{8}{3} E_X This combined efficiency of X and Z completes 83EX\frac{8}{3} E_X of the work per day. Over 8 days, the work they complete is: Work completed by X and Z in 8 days=8×83EX=643EX\text{Work completed by X and Z in 8 days} = 8 \times \frac{8}{3} E_X = \frac{64}{3} E_X But we know that the remaining work after Y leaves is 2W3\frac{2W}{3}. Therefore: 643EX=2W3\frac{64}{3} E_X = \frac{2W}{3} Solving for EXE_X: EX=2W64=W32E_X = \frac{2W}{64} = \frac{W}{32}

Step 3: Efficiency of Y

From the total work equation, we know that X and Y together complete W12\frac{W}{12} of the work per day. Thus: EX+EY=W12E_X + E_Y = \frac{W}{12} Substitute EX=W32E_X = \frac{W}{32}: W32+EY=W12\frac{W}{32} + E_Y = \frac{W}{12} Solve for EYE_Y: EY=W12W32=8W3W96=5W96E_Y = \frac{W}{12} - \frac{W}{32} = \frac{8W - 3W}{96} = \frac{5W}{96}

Step 4: Time taken by Y alone to complete the work

If Y works alone, the time taken to complete the work is: Time taken by Y=WEY=W5W96=965=19.2 days\text{Time taken by Y} = \frac{W}{E_Y} = \frac{W}{\frac{5W}{96}} = \frac{96}{5} = 19.2 \text{ days}

Thus, Y can complete the whole work alone in 19.2 days.


Would you like any further details on the steps? Here are some related questions:

  1. How do you calculate the total work in such problems?
  2. How does the change in efficiency of workers affect the time to complete work?
  3. What if the efficiencies of all workers were proportional to another unit of work?
  4. How can you solve for multiple unknown efficiencies simultaneously?
  5. Can such problems be generalized to more than 3 workers?

Tip: Always double-check units when calculating efficiencies to avoid errors in the final steps!

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Math Problem Analysis

Mathematical Concepts

Work and Time
Efficiency

Formulas

Work done = Time × Efficiency
Combined efficiency of workers = Sum of individual efficiencies

Theorems

Work and Time Principle: Total work is constant, and work is a product of time and efficiency.

Suitable Grade Level

Grades 10-12