Math Problem Statement

X, Y and Z can complete a piece of work in 36 days, 90 days and 54 days respectively. All the three started the work together but Y left after ten days and X left the work after two more days. In how many days was the entire work completed?

Solution

To solve this problem, we need to determine how much work each person (X, Y, and Z) completes in a day and then track their contributions over the given days.

Step 1: Calculate the Work Rates of X, Y, and Z

  • X can complete the work in 36 days.
    So, X’s work rate is 136\frac{1}{36} of the work per day.

  • Y can complete the work in 90 days.
    So, Y’s work rate is 190\frac{1}{90} of the work per day.

  • Z can complete the work in 54 days.
    So, Z’s work rate is 154\frac{1}{54} of the work per day.

Step 2: Calculate the Work Done by X, Y, and Z in the First 10 Days

For the first 10 days, all three (X, Y, and Z) work together.

The combined work rate for X, Y, and Z is:

Total work rate=136+190+154\text{Total work rate} = \frac{1}{36} + \frac{1}{90} + \frac{1}{54}

To add these fractions, first find the least common denominator (LCD), which is 540.

136=15540,190=6540,154=10540\frac{1}{36} = \frac{15}{540}, \quad \frac{1}{90} = \frac{6}{540}, \quad \frac{1}{54} = \frac{10}{540}

Adding these:

Total work rate=15540+6540+10540=31540\text{Total work rate} = \frac{15}{540} + \frac{6}{540} + \frac{10}{540} = \frac{31}{540}

This is the amount of work done per day by all three together.

So, the work done in the first 10 days is:

Work done in 10 days=10×31540=310540=3154\text{Work done in 10 days} = 10 \times \frac{31}{540} = \frac{310}{540} = \frac{31}{54}

Step 3: Calculate the Work Done After Y Leaves

After 10 days, Y leaves the work. Now, only X and Z continue working together.

Their combined work rate is:

X + Z’s work rate=136+154\text{X + Z’s work rate} = \frac{1}{36} + \frac{1}{54}

The LCD for 36 and 54 is 108.

136=3108,154=2108\frac{1}{36} = \frac{3}{108}, \quad \frac{1}{54} = \frac{2}{108}

Adding these:

X + Z’s work rate=3108+2108=5108\text{X + Z’s work rate} = \frac{3}{108} + \frac{2}{108} = \frac{5}{108}

They work together for 2 days before X leaves. The work done in these 2 days is:

Work done in 2 days=2×5108=10108=554\text{Work done in 2 days} = 2 \times \frac{5}{108} = \frac{10}{108} = \frac{5}{54}

Step 4: Calculate the Remaining Work and Z’s Contribution

Total work done so far is:

Total work=3154+554=3654=23\text{Total work} = \frac{31}{54} + \frac{5}{54} = \frac{36}{54} = \frac{2}{3}

So, the remaining work is:

123=131 - \frac{2}{3} = \frac{1}{3}

Now, Z alone works to complete the remaining 13\frac{1}{3} of the work. Z’s work rate is 154\frac{1}{54} per day.

The time taken by Z to complete 13\frac{1}{3} of the work is:

Time=13154=13×54=18 days\text{Time} = \frac{\frac{1}{3}}{\frac{1}{54}} = \frac{1}{3} \times 54 = 18 \text{ days}

Step 5: Calculate the Total Time Taken

The total time taken to complete the work is:

  • 10 days (when X, Y, and Z worked together)
  • 2 days (when X and Z worked together)
  • 18 days (when Z worked alone)

Total time=10+2+18=30 days\text{Total time} = 10 + 2 + 18 = 30 \text{ days}

Final Answer

The entire work was completed in 30 days.


Would you like further details or have any questions?

Here are 5 related questions:

  1. How would the solution change if Y left after 5 days instead of 10?
  2. What if Z’s efficiency increased, and he could finish the work in 45 days?
  3. How would the work distribution change if X worked alone for the first 5 days?
  4. Can you derive a general formula for the time taken if workers leave at different stages?
  5. What if one more worker joined Z after X left?

Tip: Breaking down complex word problems into smaller steps helps prevent errors in calculations.

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Math Problem Analysis

Mathematical Concepts

Rate of work
Combined work
Days to complete

Formulas

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Theorems

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Suitable Grade Level

High School