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This problem can be solved using the concept of combined work rates.

Let the time it takes for the helper to do the job alone be \( h \) hours. We are given the following:

- The gardener can complete the job in 5 hours, so the gardener's rate is \( \frac{1}{5} \) of the job per hour.
- Together, the gardener and the helper can complete the job in 4 hours, so their combined rate is \( \frac{1}{4} \) of the job per hour.

Since the rates are additive, the combined rate of the gardener and the helper working together is:

\[
\frac{1}{5} + \frac{1}{h} = \frac{1}{4}
\]

Now, solve for \( h \):

\[
\frac{1}{5} + \frac{1}{h} = \frac{1}{4}
\]

Subtract \( \frac{1}{5} \) from both sides:

\[
\frac{1}{h} = \frac{1}{4} - \frac{1}{5}
\]

Find a common denominator for \( \frac{1}{4} \) and \( \frac{1}{5} \):

\[
\frac{1}{4} = \frac{5}{20}, \quad \frac{1}{5} = \frac{4}{20}
\]

Now subtract:

\[
\frac{1}{h} = \frac{5}{20} - \frac{4}{20} = \frac{1}{20}
\]

Thus:

\[
h = 20
\]

It would take the helper 20 hours to complete the job alone.

Do you need any further details or clarification?

Here are 5 related questions you might find useful:
1. What is the general formula for work rate problems involving multiple workers?
2. How can we solve work problems when more than two workers are involved?
3. How would the problem change if the combined work rate was given in a fraction of a job, like 0.75 of a job per hour?
4. What would happen to the helper's time if the gardener could finish in 6 hours instead of 5?
5. How can we verify the solution by substituting it back into the original equation?

**Tip:** Always check your work rate equations by ensuring the units are consistent across all terms.

A gardener can care for the Greens' property in 5 hours. If his helper assists him, they can complete the job in 4 hours. How long would it take the helper to do the job alone?

Solve the work rate problem where a gardener takes 5 hours to complete a job, and together with a helper, they finish in 4 hours. Learn how to calculate the time it takes the helper to do the job alone, using algebraic concepts and combined rate formulas. Suitable for Grades 7-9.

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