Math Problem Statement
It will take you 10 hours to paint your garage and it will take your brother 15 hours to do the same job. How long will it take if the two of you together to paint the garage?
Solution
To solve this problem, we can use the concept of work rates.
Your rate of painting is of the garage per hour, and your brother's rate is of the garage per hour. When working together, the rates add up.
- Your rate: (fraction of the garage per hour)
- Your brother's rate: (fraction of the garage per hour)
Together, your combined rate is:
To add these fractions, first find a common denominator:
So, together, you both can paint of the garage per hour.
The time it will take to paint the entire garage together is the reciprocal of your combined rate:
Answer: It will take 6 hours for both of you to paint the garage together.
Do you want more details or have any questions?
Here are 5 related questions to consider:
- What if you work faster, completing the garage in 8 hours instead of 10?
- How long would it take if your brother had some help and finished in 12 hours instead of 15?
- What if you work for 4 hours together, then finish the rest alone—how long would it take?
- How much of the garage would be painted after 3 hours of working together?
- What would happen if your brother took breaks and only worked half the time?
Tip: When combining work rates, always add the rates first, and then find the reciprocal to get the total time required for the job.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Work Rate
Fractions
Reciprocal
Formulas
Combined work rate formula: 1/a + 1/b
Reciprocal to find total time: 1 / (combined work rate)
Theorems
Work rate theorem
Suitable Grade Level
Grades 6-8
Related Recommendation
Jackie and Lisa's Combined Work Rate: How Long to Paint Together?
Calculate Time Taken by Two People to Complete a Job Together
Work Rate Problem: Andrew and Bailey Painting a House
Calculate Time for Two People to Paint a Room Together
Work Rate Problem: Solving for Individual Times with Quadratic Equation