Math Problem Statement
why completeness property does not hold for rational numbers
Solution
The Completeness Property, specifically in the context of real numbers, states that every non-empty set of real numbers that is bounded above has a least upper bound (or supremum) that is also a real number.
This property does not hold for the rational numbers () due to the presence of "gaps" in . Here’s why:
Explanation:
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Definition of Supremum: The supremum (least upper bound) of a set is the smallest real number that is greater than or equal to every element of .
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Example of a Bounded Set in : Consider the set . This is a set of all rational numbers whose squares are less than 2.
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Absence of Supremum in :
- The set is bounded above in because, for example, 2 is an upper bound (since ).
- However, the least upper bound (supremum) of in is .
- Since is irrational, it does not belong to .
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Conclusion: The set has no least upper bound in because any rational number you choose will either be less than or greater than , but never exactly equal to it. Thus, the supremum of does not exist in the rational numbers.
This example illustrates that not every non-empty set of rational numbers that is bounded above has a least upper bound in , hence the Completeness Property does not hold.
Would you like more details or have any questions?
Here are 5 related questions:
- What is the difference between rational numbers and real numbers?
- How do irrational numbers fill the "gaps" in rational numbers?
- Can you provide another example where the supremum does not exist in ?
- How does the Completeness Property of real numbers relate to the concept of Dedekind cuts?
- What are the implications of the Completeness Property for calculus?
Tip: Understanding the properties of real numbers is crucial for studying calculus and analysis, as many fundamental theorems rely on the completeness of .
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Math Problem Analysis
Mathematical Concepts
Real Numbers
Rational Numbers
Supremum
Completeness Property
Bounded Sets
Formulas
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Theorems
Supremum Property
Completeness Axiom of Real Numbers
Suitable Grade Level
Grades 11-12 and above (pre-calculus, calculus, or real analysis)
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