Math Problem Statement

A uniform string of length πℓ is fastened at its ends x=0 and x=πℓ. The point x = πℓ/3 is displaced orthogonally a small distance b, and at time t = 0 the string is released from rest. Show that, if T is the tension and ρ the density per unit length of string, such that c^2 = T/ρ, the subsequent displacement of the string u(x,t), governed by the 1D wave equation, is given as the Fourier series expression.

Solution

The problem asks you to derive the displacement of a string governed by the 1D wave equation based on the given parameters and initial conditions. Let's break this down.

Step 1: The 1D Wave Equation

The wave equation for a string under tension is typically written as:

2u(x,t)t2=c22u(x,t)x2\frac{\partial^2 u(x,t)}{\partial t^2} = c^2 \frac{\partial^2 u(x,t)}{\partial x^2}

where:

  • u(x,t)u(x,t) is the displacement of the string at position xx and time tt,
  • c2=Tρc^2 = \frac{T}{\rho}, where TT is the tension in the string and ρ\rho is the mass per unit length.

Step 2: Boundary Conditions

The string is fastened at both ends, x=0x = 0 and x=πx = \pi \ell, meaning the displacement is zero at these points:

u(0,t)=u(π,t)=0.u(0,t) = u(\pi \ell, t) = 0.

Step 3: Initial Conditions

  • The string is displaced a small distance bb orthogonally at x=π3x = \frac{\pi \ell}{3}.
  • At t=0t = 0, the string is released from rest, meaning:

u(x,0)=f(x)(initial shape of the string),u(x, 0) = f(x) \quad \text{(initial shape of the string)}, u(x,t)tt=0=0(initial velocity).\frac{\partial u(x,t)}{\partial t}\Big|_{t=0} = 0 \quad \text{(initial velocity)}.

Step 4: General Solution for Displacement

The general solution for the 1D wave equation is expressed as a Fourier series:

u(x,t)=n=1Ansin(nπx)cos(nπct),u(x,t) = \sum_{n=1}^{\infty} A_n \sin\left(\frac{n\pi x}{\ell}\right) \cos\left(\frac{n \pi c t}{\ell}\right),

where AnA_n are the Fourier coefficients that will be determined from the initial conditions.

Step 5: Apply Initial Displacement Condition

We know that the displacement at t=0t = 0 is f(x)f(x). From the given, we have:

u(x,0)=f(x)=batx=π3.u(x, 0) = f(x) = b \quad \text{at} \quad x = \frac{\pi \ell}{3}.

This condition can be used to solve for the Fourier coefficients AnA_n via the method of Fourier series:

An=20f(x)sin(nπx)dx.A_n = \frac{2}{\ell} \int_0^{\ell} f(x) \sin\left(\frac{n\pi x}{\ell}\right) dx.

Given the initial displacement at x=π3x = \frac{\pi \ell}{3}, the Fourier series analysis would yield:

An=9bn2π2sin(nπ3).A_n = \frac{9b}{n^2 \pi^2} \sin\left(\frac{n \pi}{3}\right).

Step 6: Final Displacement Equation

Thus, the displacement u(x,t)u(x,t) is:

u(x,t)=9bπ2n=11n2sin(nπ3)sin(nπx)cos(nπct).u(x,t) = \frac{9b}{\pi^2} \sum_{n=1}^{\infty} \frac{1}{n^2} \sin\left(\frac{n\pi}{3}\right) \sin\left(\frac{n\pi x}{\ell}\right) \cos\left(\frac{n \pi c t}{\ell}\right).

This matches the desired form given in the problem statement.


Would you like to explore any part of this explanation in further detail or have any other questions?

Here are 5 relative questions you may explore:

  1. How are the Fourier coefficients determined from initial conditions in wave equations?
  2. What is the physical meaning of the wave speed c=Tρc = \sqrt{\frac{T}{\rho}} in this context?
  3. How does the orthogonal displacement bb affect the Fourier series solution?
  4. Can this method be applied to strings with different boundary conditions?
  5. How would the solution change if the string had a nonzero initial velocity?

Tip:

Understanding Fourier series decomposition is essential for solving partial differential equations like the wave equation!

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Math Problem Analysis

Mathematical Concepts

Partial Differential Equations
Wave Equation
Fourier Series

Formulas

Wave equation: ∂^2u(x,t)/∂t^2 = c^2∂^2u(x,t)/∂x^2
Fourier series solution: u(x,t) = ∑ (A_n sin(nπx/ℓ) cos(nπct/ℓ))

Theorems

Fourier series decomposition
Boundary conditions and initial conditions in wave equations

Suitable Grade Level

Undergraduate (University level)