Math Problem Statement

A string is tightly stretched, and its ends are fastened at two points x = 0 and x = L. Initially, the string is in the form f(x) = kx(L - x), and then released from that position. Find the displacement at any point on the string at a distance x from one end and at any time t > 0

Solution

The problem involves finding the displacement u(x,t)u(x, t) of a tightly stretched string, where the string is fixed at both ends x=0x = 0 and x=Lx = L, and the initial shape of the string is given by f(x)=kx(Lx)f(x) = kx(L - x). This is a standard wave equation problem, and we will solve it using the method of separation of variables.

Step 1: Wave Equation Setup

The wave equation for a string stretched between two points is given by:

2ut2=c22ux2\frac{\partial^2 u}{\partial t^2} = c^2 \frac{\partial^2 u}{\partial x^2}

where u(x,t)u(x, t) is the displacement of the string, and cc is the wave speed.

Step 2: Boundary Conditions

The string is fastened at the ends x=0x = 0 and x=Lx = L, so the boundary conditions are:

u(0,t)=0andu(L,t)=0for all tu(0, t) = 0 \quad \text{and} \quad u(L, t) = 0 \quad \text{for all } t

Step 3: Initial Conditions

  1. Initial displacement: At t=0t = 0, the string is initially in the form f(x)=kx(Lx)f(x) = kx(L - x), so: u(x,0)=kx(Lx)u(x, 0) = kx(L - x)

  2. Initial velocity: The string is released from rest, so the initial velocity is zero: ut(x,0)=0\frac{\partial u}{\partial t}(x, 0) = 0

Step 4: Solution Using Separation of Variables

To solve this, we use the method of separation of variables. We assume the solution takes the form:

u(x,t)=X(x)T(t)u(x, t) = X(x)T(t)

Substituting this into the wave equation:

X(x)T(t)=c2X(x)T(t)X(x)T''(t) = c^2 X''(x)T(t)

Dividing both sides by X(x)T(t)X(x)T(t):

[ \frac{T''(t)}

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Partial Differential Equations
Wave Equation
Separation of Variables

Formulas

Wave equation: ∂²u/∂t² = c²∂²u/∂x²
Initial displacement: u(x, 0) = kx(L - x)
Initial velocity: ∂u/∂t(x, 0) = 0

Theorems

Separation of Variables
Superposition Principle for Wave Equations

Suitable Grade Level

Undergraduate