Assume we have an ideal rotary potentiometer (no wiper resistance, perfect linearity, 0% tolerance) that has offers 300 degrees of rotation.

Assume we apply 5V to one end and GND to the other like the picture below. Which function represents the voltage at Vout as a function of the angle of the potentiometer in degrees. Assume that an angle of 0 degrees means the wiper is at GND.

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Group of answer choices

Vout = angle / 60

Vout = angle / 72

Vout = 5 - angle / 60

Vout = 5 - angle / 72

In this problem, we need to determine the relationship between the angle of the potentiometer and the output voltage, \( V_{out} \), given a few key points:

- The potentiometer offers 300 degrees of rotation.
- A voltage of 5V is applied to one end and GND (0V) to the other.
- The wiper moves from 0 degrees (at GND) to 300 degrees (at 5V).

### Key points:
1. At 0 degrees, \( V_{out} = 0V \) because the wiper is at GND.
2. At 300 degrees, \( V_{out} = 5V \) because the wiper is at the end connected to 5V.

Since the potentiometer is ideal with perfect linearity, the relationship between the angle and the output voltage is linear. This means that the output voltage increases at a constant rate as the angle increases from 0 to 300 degrees.

### Step-by-step calculation:
- When the wiper is at an angle \( \theta \), the fraction of the total rotation is \( \theta / 300 \).
- The corresponding voltage at that position is the same fraction of 5V, so \( V_{out} = \frac{\theta}{300} \times 5 \).

Simplifying this expression:

\[
V_{out} = \frac{5}{300} \times \theta = \frac{\theta}{60}
\]

Thus, the correct function for \( V_{out} \) as a function of the angle is:

\[
Vout = \frac{\theta}{60}
\]

### Answer:
The correct choice is **Vout = angle / 60**.

Would you like further details or have any questions?

Here are 5 relative questions to explore:
1. How does the output voltage change if the potentiometer rotation range is increased?
2. What happens to the output voltage if the applied voltage is 3V instead of 5V?
3. Can you explain how the linearity assumption affects the outcome?
4. How would adding wiper resistance change the behavior of this potentiometer?
5. What is the significance of tolerance in real potentiometers?

**Tip:** Understanding the linearity of potentiometers helps when designing circuits where precise control of voltage is required.

Assume we have an ideal rotary potentiometer (no wiper resistance, perfect linearity, 0% tolerance) that has offers 300 degrees of rotation. Assume we apply 5V to one end and GND to the other like the picture below. Which function represents the voltage at Vout as a function of the angle of the potentiometer in degrees. Assume that an angle of 0 degrees means the wiper is at GND.

Learn how to calculate the output voltage of an ideal rotary potentiometer with 300 degrees of rotation and 5V applied. This problem involves linear functions and proportionality, showing the relationship between angle and voltage in an electric circuit. Suitable for Grades 10-12.

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