The question is about calculating the current through the second resistor using data from a potentiometer.

Given information:

• The potential difference across the first resistor (58 ohms) is 2.6 V.
• We are looking to find the current through the second resistor from 582 to the equilibrium point.

Step-by-step solution:

1. Potential Difference Across First Resistor:

   • Using Ohm's Law: $V = IR$
   • Rearranging to find the current $I$:
     $I = \frac{V}{R} = \frac{2.6 \text{ V}}{58 \text{ ohms}} = 0.0448 \text{ A} = 44.8 \text{ mA}$

   This current is flowing through the first resistor of 58 ohms.

2. Balance Length and Second Resistor:

   • The second resistor is measured from 582 (likely a balance length value) to the equilibrium point.
   • We do not have explicit information about the resistance value of the second resistor, but it could be inferred using the ratio of lengths, assuming the potentiometer setup is uniform.
   • If the ratio of the balance length across the second resistor is provided or assumed based on the length, we can calculate the resistance and apply Ohm's Law again to find the current.

Final Conclusion:

Without the exact resistance value or clear ratio of the potentiometer's length, the current across the second resistor depends on additional information such as the total resistance or voltage. Assuming the circuit is balanced and the current is the same, the current would still be approximately 44.8 mA if the resistors are connected in series.

Let me know if you'd like to provide more details or want further clarifications.

Next Steps:

1. What is the exact resistance of the second resistor?
2. Is there a uniform proportionality in the balance lengths?
3. Is the circuit a series or parallel setup?
4. How does the balance length ratio relate to resistance values?
5. Do you need clarification on Ohm’s Law?

Tip: Always ensure that the potentiometer balance lengths are directly related to resistance when calculating using a potentiometer setup.