Math Problem Statement

Verify the given geometric property. Use slopes to show that A(3, 2), B(13, 4), C(12, 9), and D(2, 7) are vertices of a rectangle. We first plot the points to find the pairs of points that determine each side. Next we find the slopes of the four sides. The slope of AB is , the slope of AD is , the slope of BC is , and the slope of CD is . Two sides are parallel if their slopes are . Thus, we see that AB and are parallel to each other and AD and are parallel to each other. Two lines are perpendicular to one another when the product of their slopes is equal to . Since (slope of AB) ✕ (slope of AD) = , the sides AB and AD are perpendicular to each other. Therefore, the points A, B, C, and D are vertices of a rectangle.

Solution

To verify that points A(3,2)A(3, 2), B(13,4)B(13, 4), C(12,9)C(12, 9), and D(2,7)D(2, 7) are the vertices of a rectangle, we will use the following steps:

Step 1: Calculate the slopes of the sides

The slope of a line between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by: m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} We will compute the slopes of the following sides: ABAB, ADAD, BCBC, and CDCD.

  1. Slope of AB (between A(3,2)A(3, 2) and B(13,4)B(13, 4)): mAB=42133=210=15m_{AB} = \frac{4 - 2}{13 - 3} = \frac{2}{10} = \frac{1}{5}

  2. Slope of AD (between A(3,2)A(3, 2) and D(2,7)D(2, 7)): mAD=7223=51=5m_{AD} = \frac{7 - 2}{2 - 3} = \frac{5}{-1} = -5

  3. Slope of BC (between B(13,4)B(13, 4) and C(12,9)C(12, 9)): mBC=941213=51=5m_{BC} = \frac{9 - 4}{12 - 13} = \frac{5}{-1} = -5

  4. Slope of CD (between C(12,9)C(12, 9) and D(2,7)D(2, 7)): mCD=79212=210=15m_{CD} = \frac{7 - 9}{2 - 12} = \frac{-2}{-10} = \frac{1}{5}

Step 2: Verify if sides are parallel

Two lines are parallel if their slopes are equal.

  • Compare mABm_{AB} and mCDm_{CD}: mAB=15,mCD=15m_{AB} = \frac{1}{5}, \quad m_{CD} = \frac{1}{5} Thus, ABCDAB \parallel CD.

  • Compare mADm_{AD} and mBCm_{BC}: mAD=5,mBC=5m_{AD} = -5, \quad m_{BC} = -5 Thus, ADBCAD \parallel BC.

Step 3: Verify if sides are perpendicular

Two lines are perpendicular if the product of their slopes is 1-1.

  • Check if ABAB and ADAD are perpendicular: mAB×mAD=15×(5)=1m_{AB} \times m_{AD} = \frac{1}{5} \times (-5) = -1 Thus, ABADAB \perp AD.

This confirms that sides ABAB and ADAD are perpendicular. Similarly, since the opposite sides are parallel and adjacent sides are perpendicular, the points form a rectangle.

Conclusion:

The points A(3,2)A(3, 2), B(13,4)B(13, 4), C(12,9)C(12, 9), and D(2,7)D(2, 7) are vertices of a rectangle because opposite sides are parallel, and adjacent sides are perpendicular.

Would you like more details or have any questions?

Relative questions:

  1. How do you calculate the distance between two points in geometry?
  2. Can the same method be used to verify if points form a square?
  3. What is the significance of the slopes being equal for parallel lines?
  4. How do you confirm that a quadrilateral is a parallelogram using slopes?
  5. What are the conditions to check if a quadrilateral is a rhombus?

Tip:

Always verify perpendicularity by checking if the product of slopes is 1-1, which confirms the right angle between two sides.

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Math Problem Analysis

Mathematical Concepts

Geometry
Coordinate Geometry
Slopes of Lines
Parallel and Perpendicular Lines

Formulas

Slope formula: m = (y2 - y1) / (x2 - x1)
Perpendicular slope condition: m1 × m2 = -1
Parallel slope condition: m1 = m2

Theorems

Parallel Line Theorem
Perpendicular Line Theorem

Suitable Grade Level

Grades 9-11