Math Problem Statement

Verify the given geometric property. Use slopes to show that A(3, 2), B(13, 4), C(12, 9), and D(2, 7) are vertices of a rectangle. We first plot the points to find the pairs of points that determine each side. Next we find the slopes of the four sides. The slope of AB is Correct: Your answer is correct. , the slope of AD is Incorrect: Your answer is incorrect. , the slope of BC is Correct: Your answer is correct. , and the slope of CD is Correct: Your answer is correct. . Two sides are parallel if their slopes are Changed: Your submitted answer was incorrect. Your current answer has not been submitted. . Thus, we see that AB and Changed: Your submitted answer was incorrect. Your current answer has not been submitted. are parallel to each other and AD and Correct: Your answer is correct. are parallel to each other. Two lines are perpendicular to one another when the product of their slopes is equal to Incorrect: Your answer is incorrect. . Since (slope of AB) ✕ (slope of AD) = Correct: Your answer is correct. , the sides AB and AD are perpendicular to each other. Therefore, the points A, B, C, and D are vertices of a rectangle.

Solution

To verify that the points A(3,2),B(13,4),C(12,9),D(2,7)A(3, 2), B(13, 4), C(12, 9), D(2, 7) are vertices of a rectangle using slopes, we follow these steps:

Step 1: Calculate the slopes of the sides.

The slope of a line passing through two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by:

slope=y2y1x2x1\text{slope} = \frac{y_2 - y_1}{x_2 - x_1}

  1. Slope of AB (between points A(3,2)A(3, 2) and B(13,4)B(13, 4)):

slope of AB=42133=210=15\text{slope of AB} = \frac{4 - 2}{13 - 3} = \frac{2}{10} = \frac{1}{5}

  1. Slope of AD (between points A(3,2)A(3, 2) and D(2,7)D(2, 7)):

slope of AD=7223=51=5\text{slope of AD} = \frac{7 - 2}{2 - 3} = \frac{5}{-1} = -5

  1. Slope of BC (between points B(13,4)B(13, 4) and C(12,9)C(12, 9)):

slope of BC=941213=51=5\text{slope of BC} = \frac{9 - 4}{12 - 13} = \frac{5}{-1} = -5

  1. Slope of CD (between points C(12,9)C(12, 9) and D(2,7)D(2, 7)):

slope of CD=79212=210=15\text{slope of CD} = \frac{7 - 9}{2 - 12} = \frac{-2}{-10} = \frac{1}{5}

Step 2: Check for parallel sides.

For a rectangle, opposite sides must be parallel. Two sides are parallel if their slopes are equal.

  • Slope of AB =15= \frac{1}{5} and slope of CD =15= \frac{1}{5}. Therefore, AB is parallel to CD.
  • Slope of AD =5= -5 and slope of BC =5= -5. Therefore, AD is parallel to BC.

Step 3: Check for perpendicular sides.

For a rectangle, adjacent sides must be perpendicular. Two lines are perpendicular if the product of their slopes is 1-1.

  • Slope of AB =15= \frac{1}{5} and slope of AD =5= -5.

(15)×(5)=1\left(\frac{1}{5}\right) \times (-5) = -1

This confirms that AB is perpendicular to AD.

Conclusion:

Since opposite sides are parallel and adjacent sides are perpendicular, the points A(3,2),B(13,4),C(12,9),D(2,7)A(3, 2), B(13, 4), C(12, 9), D(2, 7) form a rectangle.

Would you like any further details or have any questions?

Related Questions:

  1. How can you use the distance formula to further verify this is a rectangle?
  2. How do you verify if four points form a square instead of a rectangle?
  3. What happens if the slopes are equal but the points don't form a closed shape?
  4. Can you generalize this method for any quadrilateral to check its type?
  5. How do you calculate the area of this rectangle using the given points?

Tip:

When using slopes to determine perpendicularity, always remember that the product of the slopes of two perpendicular lines is 1-1.

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Math Problem Analysis

Mathematical Concepts

Geometry
Coordinate Geometry
Slopes
Parallel and Perpendicular Lines

Formulas

Slope formula: (y2 - y1) / (x2 - x1)
Condition for parallel lines: Equal slopes
Condition for perpendicular lines: Product of slopes equals -1

Theorems

Slope Theorem for Parallel Lines
Slope Theorem for Perpendicular Lines

Suitable Grade Level

Grades 9-12