https://file.aiquickdraw.com/mathbot/file/1726231492557v8yrnu9c.jpg

We can solve this using the first equation of motion:

\[
v = u + at
\]

Where:
- \( v \) is the final velocity,
- \( u \) is the initial velocity (which is 0, since the particle starts from rest),
- \( a \) is the acceleration (given as \( 9 \, \text{m/s}^2 \)),
- \( t \) is the time (given as 4 seconds).

Now, plug in the values:

\[
v = 0 + (9 \, \text{m/s}^2) \times (4 \, \text{sec}) = 36 \, \text{m/s}
\]

Thus, the velocity after 4 seconds is **36 m/s**.

Do you have any further questions or want more details?

Here are 5 related questions for practice:
1. What is the velocity after 6 seconds if the acceleration is 9 m/s²?
2. If the particle had an initial velocity of 5 m/s, what would its velocity be after 4 seconds?
3. How far does the particle travel in the first 4 seconds?
4. What is the velocity if the particle starts from rest and accelerates at 12 m/s² for 5 seconds?
5. How long does it take for the particle to reach a velocity of 50 m/s with an acceleration of 9 m/s²?

**Tip**: When dealing with constant acceleration problems, always choose the right kinematic equation based on the known variables.

A particle starts from rest with constant acceleration of 9 m/s², what is its velocity after 4 seconds?

Learn how to calculate the velocity of a particle after 4 seconds when starting from rest with a constant acceleration of 9 m/s². This step-by-step kinematic solution involves using the first equation of motion. Suitable for Grades 9-10 students.

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