https://file.aiquickdraw.com/mathbot/file/1734662752485fnzxidyb.jpg

### Problem Breakdown:
We are tasked with finding the velocity of an object that starts from rest and accelerates at a constant rate for a given time.

---

### Key Information:
1. **Initial velocity (\(v_0\))**: \( 0 \, \text{m/s}\) (starts from rest).  
2. **Acceleration (\(a\))**: \(3.0 \, \text{m/s}^2\).  
3. **Time (\(t\))**: \(6.0 \, \text{seconds}\).  
4. **Formula** for velocity under constant acceleration:  
   \[
   v = v_0 + a \cdot t
   \]

---

### Substitution:
\[
v = 0 \, \text{m/s} + (3.0 \, \text{m/s}^2)(6.0 \, \text{s})
\]
\[
v = 18.0 \, \text{m/s}
\]

---

### Final Answer:
The velocity of the object at the end of \(6.0 \, \text{s}\) is:  
\[
\boxed{18.0 \, \text{m/s}}
\]

---

Would you like additional details or clarification? Let me know!  

---

Here are **5 related questions** for further exploration:  
1. What would the final velocity be if the acceleration were \(5.0 \, \text{m/s}^2\)?  
2. How would the velocity change if the object had an initial velocity of \(2.0 \, \text{m/s}\)?  
3. What is the displacement of the object over \(6.0 \, \text{s}\) under these conditions?  
4. How does the time of acceleration affect the final velocity?  
5. If the acceleration is halved, how does it affect the velocity after \(6.0 \, \text{s}\)?  

**Tip**: Always identify whether the problem involves constant or changing acceleration before selecting a formula.

An object starting from rest accelerates at a rate of 3.0 meters/seconds squared for 6.0 seconds. The velocity of the object at the end of this time is:

Learn how to find the velocity of an object starting from rest that accelerates at 3.0 m/s² for 6.0 seconds. A step-by-step explanation is provided using kinematic equations. Suitable for high school physics students.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation