Given the coordinates:
- Point A=(8,0,8)
- Point B=(0,4,0)
- Point P=(−6,10,6)
The vector F goes from point A to point B, so:
F=AB=B−A
Step-by-Step Solution:
- Calculate Vector AB:
AB=(xB−xA,yB−yA,zB−zA)=(0−8,4−0,0−8)
AB=(−8,4,−8)
- Magnitude of Vector AB:
∣AB∣=(−8)2+42+(−8)2
∣AB∣=64+16+64=144=12
- Unit Vector in the Direction of AB:
uAB=∣AB∣AB=(12−8,124,12−8)
uAB=(−32,31,−32)
- Vector from Point A to Point P:
AP=P−A=(−6−8,10−0,6−8)
AP=(−14,10,−2)
- Projection of Vector AP onto AB:
The projection formula is:
ProjABAP=(AP⋅uAB)uAB
First, compute the dot product:
AP⋅uAB=(−14)(−32)+10(31)+(−2)(−32)
AP⋅uAB=328+310+34=342=14
- Final Projection Value:
ProjABAP=14⋅(−32,31,−32)
ProjABAP=(−328,314,−328)
Conclusion:
The projection of vector AP onto the direction of AB is:
(−328,314,−328)
Would you like further details on this solution, or have any questions?
Here are some related questions for you:
- How is the dot product used to find projections?
- What is the geometric interpretation of a vector projection?
- Can you calculate the angle between vectors AB and AP?
- How does the magnitude of a vector affect its unit vector?
- What are some practical applications of vector projections in physics?
Tip: When working with vectors, always visualize them in 3D space to understand their relative directions and magnitudes better!