Math Problem Statement

Use the change-of-base formula and a calculator to evaluate each logarithm. Round your answer to three decimal places: log_√19 (3)

Solution

To solve the logarithmic expression using the change-of-base formula, let's follow these steps:

Expression:

log193\log_{\sqrt{19}}{3}

Step 1: Change-of-base formula

The change-of-base formula for logarithms is: logba=logcalogcb\log_b{a} = \frac{\log_c{a}}{\log_c{b}} Where bb is the base and aa is the argument. Here b=19b = \sqrt{19} and a=3a = 3.

Using this, we get: log193=log3log19\log_{\sqrt{19}}{3} = \frac{\log{3}}{\log{\sqrt{19}}}

Step 2: Simplify the base

Since log19=log191/2=12log19\log{\sqrt{19}} = \log{19^{1/2}} = \frac{1}{2} \log{19}, we can rewrite the expression as: log193=log312log19=2log3log19\log_{\sqrt{19}}{3} = \frac{\log{3}}{\frac{1}{2} \log{19}} = \frac{2 \log{3}}{\log{19}}

Step 3: Calculate the values using a calculator

We can now use approximate values for the logarithms (base 10):

  • log30.4771\log{3} \approx 0.4771
  • log191.2788\log{19} \approx 1.2788

Substitute these values: log193=2×0.47711.2788=0.95421.27880.7462\log_{\sqrt{19}}{3} = \frac{2 \times 0.4771}{1.2788} = \frac{0.9542}{1.2788} \approx 0.7462

Final Answer:

log1930.746\log_{\sqrt{19}}{3} \approx 0.746

Do you have any questions, or would you like further details on the process?


Here are 5 related questions for practice:

  1. How would you solve log255\log_{\sqrt{25}}{5}?
  2. Can you simplify log255\log_{25}{5} without the change-of-base formula?
  3. What is the value of log381\log_3{81}?
  4. How do you apply the change-of-base formula to logarithms with a base ee?
  5. How does the logarithmic property logb(xn)=nlogbx\log_b{(x^n)} = n \log_b{x} apply in this problem?

Tip: When solving logarithmic problems, remember that simplifying the base using exponent rules often makes the calculation much easier.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Change-of-Base Formula
Exponents

Formulas

Change-of-Base Formula: log_b (a) = log_c (a) / log_c (b)
Exponent Property: log(√x) = 1/2 log(x)

Theorems

Change-of-Base Theorem

Suitable Grade Level

Grades 9-12