Math Problem Statement

Use common logarithms or natural logarithms and a calculator to evaluate the expression.

log Subscript 19 Baseline 12log1912

Question content area bottom

Part 1

Evaluate the expression.

log Subscript 19 Baseline 12log1912almost equals≈enter your response here

​(Type an integer or a decimal. Do not round until the final answer. Then round to four decimal places as​ needed.)

Solution

To evaluate the expression log19(12)\log_{19}(12), you can use the change of base formula. The change of base formula states:

logb(a)=logc(a)logc(b)\log_{b}(a) = \frac{\log_c(a)}{\log_c(b)}

where cc can be any positive number (usually 10 for common logarithms or ee for natural logarithms).

Let's use common logarithms (base 10):

log19(12)=log10(12)log10(19)\log_{19}(12) = \frac{\log_{10}(12)}{\log_{10}(19)}

Now, let's compute this using a calculator.

  1. Compute log10(12)\log_{10}(12).
  2. Compute log10(19)\log_{10}(19).
  3. Divide the result from step 1 by the result from step 2.

I'll do this calculation for you.The value of log19(12)\log_{19}(12) is approximately 0.84390.8439 when rounded to four decimal places.

Would you like more details on this process or have any questions?

Here are some related questions:

  1. How do you use the natural logarithm to evaluate log19(12)\log_{19}(12)?
  2. What is the change of base formula and when is it used?
  3. How do logarithms relate to exponents?
  4. What is the difference between common logarithms and natural logarithms?
  5. Can you evaluate log19(12)\log_{19}(12) using natural logarithms?
  6. How do you solve logarithmic equations with different bases?
  7. What are the properties of logarithms?
  8. How do you convert logarithms with different bases?

Tip: Always check if your calculator is set to the correct mode (degrees/radians) when working with trigonometric functions involving logarithms.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Change of Base Formula
Common Logarithms

Formulas

Change of base formula: \( \log_b(a) = \frac{\log_c(a)}{\log_c(b)} \)

Theorems

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Suitable Grade Level

Grades 11-12