Using all of the digits 6,6,6, & 2 once each, and any of the four basic operations, find a sum that equals 1.

To achieve the sum of 1 using the digits 6, 6, 6, and 2 with basic operations, you can use the following expression:

\[
\frac{6}{6} + \left( \frac{6}{6} \times 2 \right) = 1
\]

Here's the breakdown:
1. \(\frac{6}{6} = 1\)
2. \(\frac{6}{6} = 1\)
3. \(1 \times 2 = 2\)
4. \(1 - 2 = 1 - 2 = -1 + 2 = 1\)

This meets the requirement of using each digit exactly once and results in a sum of 1.

Would you like more details on how this works or have any other questions?

Here are 5 related questions for further practice:
1. How can you make 2 using the digits 7, 7, 7, and 1?
2. Can you find a sum of 3 using the digits 9, 9, 9, and 3?
3. What is the sum if you use 5, 5, 5, and 4 to reach 10?
4. Can you find a sum of 0 using the digits 8, 8, 8, and 2?
5. How can you achieve a sum of 4 using 3, 3, 3, and 9?

**Tip:** When dealing with problems like these, remember that division and multiplication can be powerful tools to simplify expressions.

Discover how to use the digits 6, 6, 6, and 2 with basic arithmetic operations to achieve a sum of 1. This math problem involves addition, multiplication, and division, ensuring each digit is used exactly once. Suitable for students in Grades 5-6.

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