Math Problem Statement

Find the length of side a. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice. A. aequals    enter your response here mi ​(Round to the nearest mile as​ needed.) B. There is no solution.

Solution

To find the length of side aa using the Law of Sines, we use the following formula:

asin(A)=bsin(B)=csin(C)\frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)}

Given: c=8 mic = 8 \text{ mi} A=107.73A = 107.73^\circ B=39.78B = 39.78^\circ C=32.49C = 32.49^\circ

We need to find aa. Using the Law of Sines, we can write:

asin(A)=csin(C)\frac{a}{\sin(A)} = \frac{c}{\sin(C)}

Plugging in the known values:

asin(107.73)=8sin(32.49)\frac{a}{\sin(107.73^\circ)} = \frac{8}{\sin(32.49^\circ)}

We need to find the sine values:

sin(107.73)0.9563\sin(107.73^\circ) \approx 0.9563 sin(32.49)0.5360\sin(32.49^\circ) \approx 0.5360

Now, plug these into the equation:

a0.9563=80.5360\frac{a}{0.9563} = \frac{8}{0.5360}

Solving for aa:

a=80.95630.53607.65040.536014.28 mia = \frac{8 \cdot 0.9563}{0.5360} \approx \frac{7.6504}{0.5360} \approx 14.28 \text{ mi}

Rounding to the nearest mile:

a14 mia \approx 14 \text{ mi}

Therefore, the length of side aa is approximately: A. a=14a = 14 mi

Would you like any more details or have any questions about the process?

Here are 5 questions you might consider asking:

  1. How do you find the length of side bb in this triangle?
  2. Can you explain how to solve a triangle using the Law of Cosines?
  3. What are the steps for solving a triangle given all three sides?
  4. How can you determine if a triangle is valid based on its angles and sides?
  5. What are the common mistakes to avoid when using the Law of Sines?

Tip: When solving trigonometric problems, make sure your calculator is set to the correct mode (degrees or radians) based on the given angles.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Law of Sines
Angle measurement

Formulas

Law of Sines: a/sin(A) = b/sin(B) = c/sin(C)

Theorems

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Suitable Grade Level

High School