Math Problem Statement

Emily was asked to make a cake for a math-themed birthday party. The cake was decorated with mathematical symbols, and the guests were math enthusiasts.     As part of the entertainment, the party organizer set up a math quiz for the guests. One of the questions was about trigonometry, and Emily was asked to help grade the quiz. The question was: 

If tant=49tant=49, what is tan(t−π)tant−π?   Help Emily find the correct answer to this question.

Enter the exact answer.

Solution

To solve for tan(tπ)\tan(t - \pi), we can use the trigonometric identity for the tangent function:

tan(tπ)=tan(t)\tan(t - \pi) = \tan(t)

This identity tells us that subtracting π\pi from the angle tt does not change the sign or the value of the tangent function. Therefore:

tan(tπ)=tan(t)\tan(t - \pi) = \tan(t)

Given that tan(t)=49\tan(t) = 49, we have:

tan(tπ)=49\tan(t - \pi) = 49

So, the exact value of tan(tπ)\tan(t - \pi) is 4949.

Would you like more details, or do you have any other questions?

Here are some related questions:

  1. What is the general identity for tan(t+π)\tan(t + \pi)?
  2. How does the tangent function behave when the angle is shifted by π2\frac{\pi}{2}?
  3. What is the period of the tangent function?
  4. What is the value of tan(π4)\tan\left(\frac{\pi}{4}\right)?
  5. How can the tangent function be derived using sine and cosine?
  6. What happens to tan(t)\tan(t) if tt is shifted by π3\frac{\pi}{3}?
  7. How is the tangent function related to the unit circle?
  8. What is the relationship between tan(t)\tan(t) and cot(t)\cot(t)?

Tip: Remember that the tangent function has a period of π\pi, meaning tan(t+π)=tan(t)\tan(t + \pi) = \tan(t).

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Math Problem Analysis

Mathematical Concepts

Trigonometry

Formulas

\( \tan(t - \pi) = \tan(t) \)

Theorems

Trigonometric identities

Suitable Grade Level

Advanced High School