Math Problem Statement

y = -3 sin(sin(2x + π/2))

Solution

The equation given is:

y=3sin(sin(2x+π2))y = -3 \sin\left(\sin\left(2x + \frac{\pi}{2}\right)\right)

The text next to it mentions a vertical translation down 2 units and a vertical stretch or shrink by the product of 1/2 and the existing function coefficient.

Let's break this down:

1. Base Function

The core of the function involves the nested sine functions:

y=3sin(sin(2x+π2))y = -3 \sin\left(\sin\left(2x + \frac{\pi}{2}\right)\right)

  • Outer Sine: The term \sin(something) indicates the sine wave behavior, with the amplitude controlled by the coefficient in front of it, which is -3 in this case.
  • Inner Sine: The inner sine, \sin(2x + \frac{\pi}{2}), is itself a sine wave, with a phase shift of π2\frac{\pi}{2} to the left and a horizontal compression due to the factor of 2 multiplying xx.

2. Vertical Stretch/Shrink

  • The coefficient of -3 causes a vertical stretch by a factor of 3, as compared to the base sine function.
  • The negative sign causes a reflection over the x-axis.

The note refers to modifying this coefficient. If the vertical stretch or shrink is further multiplied by 12\frac{1}{2}, it means that the overall amplitude will be reduced to half its current value, or:

3×12=32-3 \times \frac{1}{2} = -\frac{3}{2}

This would mean the new function would be:

y=32sin(sin(2x+π2))y = -\frac{3}{2} \sin\left(\sin\left(2x + \frac{\pi}{2}\right)\right)

3. Vertical Translation

The "vertical translation down 2 units" suggests the entire graph is shifted downward by 2 units. Thus, the final modified equation after the vertical translation would be:

y=32sin(sin(2x+π2))2y = -\frac{3}{2} \sin\left(\sin\left(2x + \frac{\pi}{2}\right)\right) - 2

This is the final equation that represents the function after both the stretch/shrink and translation.


Do you have any further questions, or would you like additional details? Here are some related questions:

  1. How does the inner sine function affect the overall shape of the graph?
  2. What is the significance of the phase shift π2\frac{\pi}{2} in this function?
  3. How does the vertical translation affect the maximum and minimum values of the sine wave?
  4. How would you find the period of the inner sine function sin(2x+π2)\sin(2x + \frac{\pi}{2})?
  5. How would the graph look if the coefficient of -3 was positive instead?

Tip: When working with nested trigonometric functions, analyze the inner function's behavior first, then apply the modifications caused by the outer function!

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Math Problem Analysis

Mathematical Concepts

Trigonometric Functions
Vertical Translation
Vertical Stretch and Shrink
Phase Shift

Formulas

y = A sin(Bx + C) + D
Vertical Stretch/Shrink: y = A sin(Bx + C)

Theorems

Sine Function Properties
Phase Shift Theorem

Suitable Grade Level

Grades 11-12