Math Problem Statement

Find the transformations of the function y = 3 sin (-2x -(pi/

Solution

It seems like the function you provided is incomplete. Based on what you've written, I assume you meant:

y=3sin(2xπ2)y = 3 \sin\left(-2x - \frac{\pi}{2}\right)

To find the transformations of this sine function, let's break it down:

The general form of a sine function is:

y=Asin(Bx+C)+Dy = A \sin(Bx + C) + D

Where:

  • AA is the amplitude (vertical stretch or shrink),
  • BB affects the period of the function (horizontal stretch or shrink),
  • CC causes a horizontal shift (phase shift),
  • DD is a vertical shift.

For the given function y=3sin(2xπ2)y = 3 \sin\left(-2x - \frac{\pi}{2}\right):

Step 1: Amplitude

  • The coefficient 33 indicates a vertical stretch by a factor of 3.
    • This means the graph will oscillate between 3 and -3 instead of 1 and -1.

Step 2: Horizontal Stretch/Shrink

  • The coefficient 2-2 inside the sine function affects the period of the graph.
    • The formula for the period of a sine function is 2πB\frac{2\pi}{|B|}.
    • In this case, B=2B = -2, so the period is: Period=2π2=π\text{Period} = \frac{2\pi}{2} = \pi
    • This means the sine wave will complete one full cycle in π\pi units, which is a horizontal shrink by a factor of 2 (because normally, it would complete one cycle in 2π2\pi).

Step 3: Phase Shift (Horizontal Shift)

  • The phase shift is determined by the formula CB\frac{-C}{B}.
    • In the equation 2xπ2-2x - \frac{\pi}{2}, C=π2C = -\frac{\pi}{2} and B=2B = -2.
    • The phase shift is: (π2)2=π22=π4\frac{-(-\frac{\pi}{2})}{-2} = \frac{\frac{\pi}{2}}{2} = \frac{\pi}{4}
    • Since the phase shift is positive, the graph shifts to the left by π4\frac{\pi}{4} units.

Step 4: Reflection

  • The negative sign in front of the 2x2x indicates a reflection across the y-axis.
    • This means the graph is flipped horizontally.

Summary of Transformations:

  1. Vertical Stretch by a factor of 3 (amplitude is 3).
  2. Horizontal Shrink by a factor of 2 (period is π\pi).
  3. Phase Shift to the left by π4\frac{\pi}{4} units.
  4. Reflection across the y-axis.

Would you like a more detailed explanation or a graph of the function?

Here are some related questions:

  1. How does the period of a sine function change when the coefficient inside the function changes?
  2. What is the effect of a negative coefficient on the amplitude of a sine function?
  3. How do you calculate the phase shift when the function is in the form y=Asin(Bx+C)+Dy = A \sin(Bx + C) + D?
  4. How does the reflection across the x-axis differ from a reflection across the y-axis in trigonometric functions?
  5. How can you use the transformations to graph the function step by step?

Tip: To quickly find the phase shift, always use the formula CB\frac{-C}{B}, but remember to consider the signs of CC and BB carefully.

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Math Problem Analysis

Mathematical Concepts

Trigonometric Functions
Sine Function Transformations

Formulas

y = A sin(Bx + C) + D
Period = 2π/|B|
Phase Shift = -C/B

Theorems

Transformations of the sine function

Suitable Grade Level

Grades 9-12