Math Problem Statement

Determine the​ amplitude, period, and phase shift of the function. Graph the function.

y equals negative 2 sine left parenthesis 3 x minus 2 pi right parenthesisy=−2sin(3x−2π)

Question content area bottom left

Part 1

The amplitude is

enter your response here.

​(Simplify your​ answer.)

Part 2

The period is

enter your response here.

​(Type an exact​ answer, using

piπ

as needed. Use integers or fractions for any numbers in the​ expression.)

Part 3

The phase shift is

enter your response here.

​(Type an exact​ answer, using

piπ

as needed. Use integers or fractions for any numbers in the​ expression.)

Part 4

Use the graphing tool to graph the function.

Solution

Let's break down the given function y=2sin(3x2π)y = -2 \sin(3x - 2\pi) step by step to determine the amplitude, period, and phase shift.

Part 1: Amplitude

The amplitude of a sine function y=Asin(Bx+C)y = A \sin(Bx + C) is given by A|A|.

Here, A=2A = -2, so the amplitude is: Amplitude=A=2=2\text{Amplitude} = |A| = |-2| = 2

Part 2: Period

The period of a sine function y=Asin(Bx+C)y = A \sin(Bx + C) is calculated as: Period=2πB\text{Period} = \frac{2\pi}{|B|} In this case, B=3B = 3, so the period is: Period=2π3\text{Period} = \frac{2\pi}{3}

Part 3: Phase Shift

The phase shift is given by CB\frac{-C}{B}, where CC is the constant inside the parentheses with xx.

Here, the equation inside the sine function is 3x2π3x - 2\pi. We can factor out the 3 from this expression: y=2sin(3(x2π3))y = -2 \sin(3(x - \frac{2\pi}{3})) Thus, the phase shift is: Phase Shift=2π3to the right\text{Phase Shift} = \frac{2\pi}{3} \quad \text{to the right}

Part 4: Graphing the Function

To graph the function y=2sin(3x2π)y = -2 \sin(3x - 2\pi):

  • The sine wave has an amplitude of 2.
  • The period is 2π3\frac{2\pi}{3}, meaning one complete cycle occurs every 2π3\frac{2\pi}{3} units along the x-axis.
  • The phase shift moves the graph 2π3\frac{2\pi}{3} units to the right.
  • Since the amplitude is negative, the graph is flipped vertically.

You can use a graphing tool to sketch the curve by plotting key points (max, min, and intercepts) and applying the transformations described above.

Recap:

  1. Amplitude = 2
  2. Period = 2π3\frac{2\pi}{3}
  3. Phase Shift = 2π3\frac{2\pi}{3} to the right

Would you like more details or clarifications on any part?

Here are 5 related questions:

  1. How would the graph change if the amplitude were positive instead of negative?
  2. What is the effect of increasing the value of BB on the period of the sine function?
  3. How does a horizontal stretch or compression affect the graph of a sine function?
  4. What happens if the phase shift moves the graph to the left instead of the right?
  5. How does the vertical translation of a sine function affect its maximum and minimum points?

Tip: Always pay attention to the sign of the amplitude when graphing, as it determines whether the sine wave starts going up or down.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Trigonometry
Sine Function
Graphing Transformations

Formulas

Amplitude: |A| = |-2| = 2
Period: 2π / |B| = 2π / 3
Phase Shift: -C / B = 2π / 3 to the right

Theorems

Trigonometric Function Properties
Graphing Sine and Cosine Functions

Suitable Grade Level

Grades 10-12